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anonymous

  • 5 years ago

When simplifying radical expressions how would you find the GCF of 5xy^3 over 6xy? I cant seem to remember :P

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  1. anonymous
    • 5 years ago
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    I am doing my lesson and they say the GCF would be 6xy and i disagree. Is that correct? It is one of the steps to solving a problem :P

  2. anonymous
    • 5 years ago
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    O_O

  3. anonymous
    • 5 years ago
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    i think it would be xy - although i have no clue how to calculate a gcd xD... i'm going to look it up - hold on :P

  4. anonymous
    • 5 years ago
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    okie dokie! :)

  5. anonymous
    • 5 years ago
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    o.O ok - it's not as easy, as i thought. But one simple way would just be to find the factors of both expressions and select the common ones... so imho \[\gcd(5xy^3, 6xy) = xy\] cause 5 and 6 don't have any common prime-factors... and well xy is obviously the highest degree, cause of the second polynom...

  6. anonymous
    • 5 years ago
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    Alright then thanks babe :D lol idk why it said the GCF would be 6xy then :P thats weird prolly technical mistake or whatever on the website :) xD so very helpful :)

  7. anonymous
    • 5 years ago
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    6xy is definitely wrong - would leave you with \[{5 \over 6} y^2\] for the first term and wikipedia says, it has to divide evenly (remainder = 0). But I guess, you already know ;) anyhow - you're very welcome! :)

  8. anonymous
    • 5 years ago
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    :)

  9. anonymous
    • 5 years ago
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    Yep i just talked to a teacher through instant chat or whatever lol and he said that they must've made a mistake :) Thanks :D

  10. anonymous
    • 5 years ago
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    Oh and do u think you could help me real quick with step on a problem im doing in another lesson real quick? :)

  11. anonymous
    • 5 years ago
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    sure..

  12. anonymous
    • 5 years ago
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    Holy pellet lol nevermind!! >.< sorry i just got what i did wrong ughhh ok im sorry and i thought u were going to bed? :D lol

  13. anonymous
    • 5 years ago
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    i am - but it's just 3 hours, so... isn't really worth the trouble ;)

  14. anonymous
    • 5 years ago
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    xD Are you gonna be ok tomorrow? I mean like you can run on empty? :o lol

  15. anonymous
    • 5 years ago
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    i'm an insomniac so i'm used to it ;) But I think I'll at least rest my eyes a little, so - cya tomorrow! :*

  16. anonymous
    • 5 years ago
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    Mkay!! :)

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