anonymous
  • anonymous
The region bounded by the curve, y=x^2+1, and the line, y=-x+3, is rotated around the x-axis to generate a solid. Find the volume of the solid.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
hey I saw you post this question earlier but you logged off
anonymous
  • anonymous
I'm gunna try and solve it will you be on?
anonymous
  • anonymous
yea glad your still on and yes i will

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anonymous
  • anonymous
do you have the Volume equation? or is it just pi*the function squared
anonymous
  • anonymous
just pi* the function squared
anonymous
  • anonymous
okay so do you have a graphing calculater
anonymous
  • anonymous
negative on that prolly should have one being in calc
anonymous
  • anonymous
its fine. You could use the calculater to see where these functions intersect. Without one, just set the equations equal to eachother and solve (do this and tell me what you get)
anonymous
  • anonymous
do you have a mac
anonymous
  • anonymous
nope one sec
anonymous
  • anonymous
I got x=1
anonymous
  • anonymous
sec
anonymous
  • anonymous
what did you intergrate
anonymous
  • anonymous
I didn't I set them to each other and solved algebra
anonymous
  • anonymous
ooh okay. yeah you get 1 and -2
anonymous
  • anonymous
so those are your domain of integration
anonymous
  • anonymous
do you have a final answer (from the book or something)
anonymous
  • anonymous
cuz I got a wierd fraction
anonymous
  • anonymous
no it's from a worksheet
anonymous
  • anonymous
this is very hard without being able to draw a graph
anonymous
  • anonymous
http://www.wolframalpha.com/input/?i=integrate&a=*C.integrate-_*Calculator.dflt-&f2=pi%28-x%2B3%29^2-pi%28x^2%2B1%29^2&f=Integral.integrand_pi%28-x%2B3%29^2-pi%28x^2%2B1%29^2&f3=-2&f=Integral.rangestart_-2&f4=1&f=Integral.rangeend_1&a=*FVarOpt.1-_**-.***Integral.variable---.**Integral.rangestart-.*Integral.rangeend---
anonymous
  • anonymous
that shows you what I set up for my integral. Its hard to explain via chat but try this: pi*(outter radius)^2 - pi*(inner radius)^2
anonymous
  • anonymous
alright thanx but why did u square each equation? how did u know to do that?
anonymous
  • anonymous
thats the volume formula
anonymous
  • anonymous
because when you rotate the shape around the x-axis its 3-dimensional. and you subtract the inner radius because thats the hole the shape makes when you rotate it. (so the shape looks like a doughnut)
anonymous
  • anonymous
ok thank you very much for your help
anonymous
  • anonymous
you are welcome let me know if you have any others.....get a graphing calc

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