A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 5 years ago
A certain population of bacteria contains 2380 individuals at noon on Monday and grows to 2430 after one hour.
Assuming the the growth is exponential, about how many will there be on noon that Wednesday?
anonymous
 5 years ago
A certain population of bacteria contains 2380 individuals at noon on Monday and grows to 2430 after one hour. Assuming the the growth is exponential, about how many will there be on noon that Wednesday?

This Question is Closed

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[2430 = 2380e ^{k}\] solve for k using ln use that k value to find second part t is in hours \[P = 2380e ^{48k}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0what does k represent?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0and im supposed to solve with using ln or logs

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[P _{t}=P _{0}e ^{kt}\] thats the general formula for exponential growth k is a constant determined by initial conditions yes because ln(e^k) = k

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0but im not supposed to ln or logs

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you have to solve this without using logs??

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i dont know that you can, here are the answers then k = 0.0208 P = 6456
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.