anonymous
  • anonymous
A certain population of bacteria contains 2380 individuals at noon on Monday and grows to 2430 after one hour. Assuming the the growth is exponential, about how many will there be on noon that Wednesday?
Mathematics
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SOLVED
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chestercat
  • chestercat
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dumbcow
  • dumbcow
\[2430 = 2380e ^{k}\] solve for k using ln use that k value to find second part t is in hours \[P = 2380e ^{48k}\]
anonymous
  • anonymous
what does k represent?
anonymous
  • anonymous
and im supposed to solve with using ln or logs

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dumbcow
  • dumbcow
\[P _{t}=P _{0}e ^{kt}\] thats the general formula for exponential growth k is a constant determined by initial conditions yes because ln(e^k) = k
anonymous
  • anonymous
but im not supposed to ln or logs
dumbcow
  • dumbcow
you have to solve this without using logs??
anonymous
  • anonymous
yes
dumbcow
  • dumbcow
i dont know that you can, here are the answers then k = 0.0208 P = 6456
anonymous
  • anonymous
thanks

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