A certain population of bacteria contains 2380 individuals at noon on Monday and grows to 2430 after one hour. Assuming the the growth is exponential, about how many will there be on noon that Wednesday?

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A certain population of bacteria contains 2380 individuals at noon on Monday and grows to 2430 after one hour. Assuming the the growth is exponential, about how many will there be on noon that Wednesday?

Mathematics
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\[2430 = 2380e ^{k}\] solve for k using ln use that k value to find second part t is in hours \[P = 2380e ^{48k}\]
what does k represent?
and im supposed to solve with using ln or logs

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Other answers:

\[P _{t}=P _{0}e ^{kt}\] thats the general formula for exponential growth k is a constant determined by initial conditions yes because ln(e^k) = k
but im not supposed to ln or logs
you have to solve this without using logs??
yes
i dont know that you can, here are the answers then k = 0.0208 P = 6456
thanks

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