## anonymous 5 years ago write the series with summation notation: 12+4+4/3+4/9. How do you set up notation?

1. anonymous

you find a common ratio (1/3) $12 * \sum_{n=?}^{?} (1/3)^{n}$

2. anonymous

I'm not entirely sure but hopefully this will somewhat help

3. anonymous

the answer is $\sum_{i=1}^{4} 4/3^{i-2}$ i just cant seem get past the common ration of 1/3.