anonymous
  • anonymous
each question of a 5 multiple exam has 4 possible answers. suppose a student picks an answer at ramdon for each question.find the prob the student slects the correct answer on only the 2nd and 3rd questions
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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dumbcow
  • dumbcow
= 3/4 * 1/4 *1/4 * 3/4*3/4 =(1/4)^2 *(3/4)^3 =(1/16)*(27/64) =27/1024
anonymous
  • anonymous
so 1024?
dumbcow
  • dumbcow
no probabilities are between 0 and 1 p = 27/1024

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anonymous
  • anonymous
that would be the answer of u have to deveide
dumbcow
  • dumbcow
if you divide it its .026367188
anonymous
  • anonymous
would u have to devide?
dumbcow
  • dumbcow
the answer in fraction form is 27/1024 the answer in decimal form is 0.026367188
anonymous
  • anonymous
which one would i use because it says problility
dumbcow
  • dumbcow
it doesn't matter since it's the same answer but typically for probability questions they want the answer in the fraction form
anonymous
  • anonymous
HELP ME I JUST POSTED A NEW ONE

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