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anonymous

  • 5 years ago

each question of a 5 multiple exam has 4 possible answers. suppose a student picks an answer at ramdon for each question.find the prob the student slects the correct answer on only the 2nd and 3rd questions

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  1. dumbcow
    • 5 years ago
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    = 3/4 * 1/4 *1/4 * 3/4*3/4 =(1/4)^2 *(3/4)^3 =(1/16)*(27/64) =27/1024

  2. anonymous
    • 5 years ago
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    so 1024?

  3. dumbcow
    • 5 years ago
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    no probabilities are between 0 and 1 p = 27/1024

  4. anonymous
    • 5 years ago
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    that would be the answer of u have to deveide

  5. dumbcow
    • 5 years ago
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    if you divide it its .026367188

  6. anonymous
    • 5 years ago
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    would u have to devide?

  7. dumbcow
    • 5 years ago
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    the answer in fraction form is 27/1024 the answer in decimal form is 0.026367188

  8. anonymous
    • 5 years ago
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    which one would i use because it says problility

  9. dumbcow
    • 5 years ago
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    it doesn't matter since it's the same answer but typically for probability questions they want the answer in the fraction form

  10. anonymous
    • 5 years ago
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    HELP ME I JUST POSTED A NEW ONE

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