each question of a 5 multiple exam has 4 possible answers. suppose a student picks an answer at ramdon for each question.find the prob the student slects the correct answer on only the 2nd and 3rd questions

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= 3/4 * 1/4 *1/4 * 3/4*3/4
=(1/4)^2 *(3/4)^3
=(1/16)*(27/64)
=27/1024

so 1024?

no probabilities are between 0 and 1
p = 27/1024

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