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anonymous
 5 years ago
each question of a 5 multiple exam has 4 possible answers. suppose a student picks an answer at ramdon for each question.find the prob the student slects the correct answer on only the 2nd and 3rd questions
anonymous
 5 years ago
each question of a 5 multiple exam has 4 possible answers. suppose a student picks an answer at ramdon for each question.find the prob the student slects the correct answer on only the 2nd and 3rd questions

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0= 3/4 * 1/4 *1/4 * 3/4*3/4 =(1/4)^2 *(3/4)^3 =(1/16)*(27/64) =27/1024

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no probabilities are between 0 and 1 p = 27/1024

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0that would be the answer of u have to deveide

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0if you divide it its .026367188

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0would u have to devide?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the answer in fraction form is 27/1024 the answer in decimal form is 0.026367188

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0which one would i use because it says problility

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0it doesn't matter since it's the same answer but typically for probability questions they want the answer in the fraction form

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0HELP ME I JUST POSTED A NEW ONE
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