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anonymous

  • 5 years ago

a cooler contains 7 cans of soda 3 colas, 3 oranges, and 1 cherry. Two cans are selected at random without replacement. Find the prob that at least one can is cola

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  1. anonymous
    • 5 years ago
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    3/7. There

  2. anonymous
    • 5 years ago
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    Oops tyop

  3. Yuki
    • 5 years ago
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    to find the probability of your case, you need to compute the prob P(exactly one can is cola) + P(exactly two cans are cola) + P(all three cans are cola) but tat will take a while so we use another technique

  4. anonymous
    • 5 years ago
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    3/7 right?

  5. Yuki
    • 5 years ago
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    sorry, not need for all three part

  6. anonymous
    • 5 years ago
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    No that was the first part but my ipad is spazzing. I'll answer if yuki cant

  7. Yuki
    • 5 years ago
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    anyway, the complement of (at least one cola) is (no cola at all) and the probability of a complement is p(complement) = 1-p(statement) so 1-p(no cola) would be easier to calculate

  8. Yuki
    • 5 years ago
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    can you find the probability that the two cans you pulled out contains no cola can ?

  9. anonymous
    • 5 years ago
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    how would u do that

  10. Yuki
    • 5 years ago
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    okay so since you are pulling out two cans from a container at random without any replacement, the the way you pull out two cans will have these following steps 1), pull out a can from 7 cans 2), pull out another from the "remaining 6" so, try to answer step 1). what is the probability of pulling out a non-cola can out of 7 ?

  11. anonymous
    • 5 years ago
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    6/7

  12. Yuki
    • 5 years ago
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    that is not right you have 4 cans that ar non-cola out of 7 so ...

  13. anonymous
    • 5 years ago
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    4/7?

  14. Yuki
    • 5 years ago
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    very good

  15. Yuki
    • 5 years ago
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    now, how many non-cola cans are there in the container left ?

  16. radar
    • 5 years ago
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    First draw 3/7 probability for a cola second draw 3/6 probality for a cola probability from both draws getting at least on cola is 92% Doesn't seem right.

  17. anonymous
    • 5 years ago
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    2

  18. anonymous
    • 5 years ago
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    NO ONE GIVE CHICKA THE ANSWER!!!!

  19. Yuki
    • 5 years ago
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    nope initially you had 4 non-cola cans right ? are you having trouble identifying what a non-cola can is ? Cherry and Orange are the non-cola cans. we had 1 cherry and 3 oranges , 4 total. since we pulled out one , so how many should be left ?

  20. anonymous
    • 5 years ago
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    3

  21. Yuki
    • 5 years ago
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    exactly, so now you are ready to answer step 2) what is the probability that you can pull out the 3 non-cola cans from the remaining 6 ?

  22. anonymous
    • 5 years ago
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    Hahaha having trouble identifying what a non-cola is...

  23. Yuki
    • 5 years ago
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    well, there is cherry cola and lime cola right ?

  24. anonymous
    • 5 years ago
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    is it .71

  25. anonymous
    • 5 years ago
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    I like Lime Cola better :)

  26. anonymous
    • 5 years ago
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    Go with that one.

  27. anonymous
    • 5 years ago
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    CAN SOMEONE HELP ME

  28. Yuki
    • 5 years ago
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    you are only two steps before the answer ok? so what was the prob of 3 cans out of 6 ?

  29. anonymous
    • 5 years ago
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    3/6

  30. Yuki
    • 5 years ago
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    very good

  31. Yuki
    • 5 years ago
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    the last step is to multiply those two probabilities, 4/7 * 3/6 = ?

  32. anonymous
    • 5 years ago
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    20.5714

  33. Yuki
    • 5 years ago
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    haha you can just use fractions you know, 2/7 anyways, remember that we were looking for the complement ? all you have to do now is to subtract this from 1. so the answer is 1 - 2/7 = ?

  34. anonymous
    • 5 years ago
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    so 5/7

  35. Yuki
    • 5 years ago
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    very good

  36. anonymous
    • 5 years ago
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    thank u

  37. Yuki
    • 5 years ago
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    Now if you really seek help, I recommend you to hire a private tutor or go to a tutoring center or an after school program. the type of help you need is not easy to obtain online and as you noticed, it takes a bit while to solve just one problem. I will be more than happy to help you but you need to relax and get help efficiently, ok? Now good luck. :)

  38. mathmagician
    • 5 years ago
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    P(there is no cola)=7/10*6/9=21/45 P(there is a least 1 cola)=1-P(there is no cola)=1-21/45=24/45

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