anonymous
  • anonymous
Evaluate the integral by interpreting it in terms of areas. (integral upper(2) lower(-2)) sqrt(4-x^2)dx
Mathematics
katieb
  • katieb
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anonymous
  • anonymous
if u take the equation of the circle \[x ^{2}+y ^{2}=2^{2}\] then u will get \[y=\sqrt{4-x ^{2}}\]. and the given integral is eqivalent to the area of the upper half of the cicle because only in the upper half y is +ve. and the ans. will be \[1/2*\pi*2^{2}=2\pi\]
anonymous
  • anonymous
ohhh thank u so much. i kept the 4 and forgot to square it so i had my radius to be 4.thanks a lot

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