## anonymous 5 years ago Evaluate the integral by interpreting it in terms of areas. (integral upper(2) lower(-2)) sqrt(4-x^2)dx

1. anonymous

if u take the equation of the circle $x ^{2}+y ^{2}=2^{2}$ then u will get $y=\sqrt{4-x ^{2}}$. and the given integral is eqivalent to the area of the upper half of the cicle because only in the upper half y is +ve. and the ans. will be $1/2*\pi*2^{2}=2\pi$

2. anonymous

ohhh thank u so much. i kept the 4 and forgot to square it so i had my radius to be 4.thanks a lot