i included a picture of the problem. its easier to show you than to type it. really appreciate your help.

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i included a picture of the problem. its easier to show you than to type it. really appreciate your help.

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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where is it?
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right there. thanks QuantumTorch.

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Sure thing. Natural log both sides and then it becomes a simple algebraic equation.
I gotta go to bed so I can't be too specific, but you get something like the x-1=(1/4)x+2 or whatever the leftover components were
I'm sorry, plus the ln of all that
\[e ^{x-1}=(1/e ^{4})^{x+2}\] \[e ^{x-1}=e ^{-4(x+2)}\] and hence \[x-1=-4x-8\] and x=-1.4
thank you for all your help

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