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- anonymous

The sum of three numbers is 12. The first number is twice the sum of the second and third. The third number is 5 less than the first. Find the number.
The key is: first is 8, second is 1, third is 3
This is complicated if you have to show your work and not just guess and check. Set up the equations first.

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- anonymous

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- anonymous

There aren't really equations. You just have to use logic. Use that Logic, process of elimination.. I'm not sure what level of math you are in though

- anonymous

this is algebra 2

- anonymous

if you set up equation I know how to solve

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- anonymous

You could maybe use probability. Are you learning about Cnr and Pnr?

- anonymous

yes I can do

- anonymous

I can solve you don't have to solve , you just help me set up equation

- anonymous

umm okay i'm not sure if this is right but

- anonymous

figure out how many sums of 3 DIFFERENT (whole) numbers add up to 12. so 12*11*10

- anonymous

so thats your total possibilities and now u can narrow it down

- anonymous

given the key

- anonymous

\[\{a+b+c=12,a=-10+2 a+2 b,c=a-5\} \]\[\{\{a\to 8,b\to 1,c\to 3\}\} \]

- anonymous

thankyou haha

- anonymous

robtobey how yu get number 10 and 5 ,

- anonymous

the key for check answer not the given

- anonymous

I'm working on a response.

- anonymous

I still don't get ,how you get -10?

- anonymous

{a + b + c = 12, a = 2 (b + c) , c = a - 5}
Replace c in the first two equations with (a-5)
{-5 + 2 a + b = 12, a = 2 (-5 + a + b)}
Expand the second equation above by multiplying through by 2
{-5 + 2 a + b == 12, a == -10 + 2 a + 2 b}
Solve the above two equations for a and b
Take the value of a and plug it into c = a - 5 to obtain the value of c
I hope I got this correct.

- anonymous

thanks

- anonymous

You are welcome.

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