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anonymous
 5 years ago
Is anyone willing to help?
anonymous
 5 years ago
Is anyone willing to help?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You said your problem had to do with Newton's law of cooling, is that the equation Y(t)=Ys+Aoe^kt?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0hey nick are you still there?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0it say's I have 2 replys yet I only saw one questioned response from nick am I doing something wrong?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0All right, I think I figured out your problem, it may take a while, but I'll explain it.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0c'mon please help? I'll show you what I think I know lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0In that equation Y(t)=Ys+Aoe^kt, the Ys=surrounding temperature at t=0. In this case, let t=0 be the 12:00 AM time. So the Ys in this problem is 65. Ao = Y(0)  Ys, which is 7865 = 13, the 78 being the temperature at time 0. So, your equation should start out looking like Y(t)=65+13e^kt.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Now, we need to solve for k. To do that, set your Y(t) to the second temperature taken, which was 74 degrees. You also know t, since the second temperature was recorded an hour later or 60 minutes later. So it should be 74=65+13e^(60k).

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Move the 65 over, which makes it 9=13e^(60k). To get rid of the e, take the log of both sides, i.e. ln(9/13)=lne^(60k).

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0That will give you ln(9/13)=60k. Solve for k and you should get something like .0061...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Now that you have the k value, you can solve for when the body died. Set the equation equal to 98.6. So you should now have 98.6=65+13e^(.0061...t)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Solve t the same way you found the k value and you will be able to determine when the boy died.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0No problem, glad I could help.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes you did I was in panic mode. The equation we were given varies but it's the same idea
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