anonymous
  • anonymous
Consider a hollow conducting sphere of a certain thickness having a charge in the center (+q). The charge will induce opposite charges on the inside face of the sphere (in accordance with Gauss' Law). There will not be an electric field in the metal part (thickness) of the conductor. Will there be an electric field in the hollow part? (i.e. between the +q and the induced charges). Now, since the induced charges come from the conductor itself, the outside of the conductor will have a charge of +q. Wont' there be an electric field between the +q charge on the surface and the induced -q char
OCW Scholar - Physics II: Electricity and Magnetism
  • Stacey Warren - Expert brainly.com
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chestercat
  • chestercat
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anonymous
  • anonymous
Continuation of the question: Now, since the induced charges come from the conductor itself, the outside of the conductor will have a charge of +q. Wont' there be an electric field between the +q charge on the surface and the induced -q charges on the inside. If so, there will be an electric field in the metal part (thickness) of the conductor??? Please explain. Are we referring to net electric field? Please show a diagram regarding the configuration of this net electric field.
anonymous
  • anonymous
Yes, we are saying the net electric field in the conductor is 0. Remember, the charges in the initially neutral conductor separated in response to the field created by the +q charge in the hollow and moved until there was no further field (force) to cause them to move. If there was residual field, charges would move in response until no net force remains

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