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anonymous

  • 5 years ago

can anyone give me some examples of problems like " whats is the solution set for (x=1)^2=49?

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  1. radar
    • 5 years ago
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    Have you stated the example correctly?

  2. anonymous
    • 5 years ago
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    dang it. no...it was (x+1)^2=49

  3. anonymous
    • 5 years ago
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    (x+1)^2=7^2 so (x+1)=plus minus (7) x=plus minus 6

  4. radar
    • 5 years ago
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    O.K look like 6 would do it so would -8. Lets work it out. \[(x+1)^{2}= x ^{2}+2x+1=49\] \[x ^{2}+2x-48=0\] \[(x+8)(x-6)=0\]

  5. anonymous
    • 5 years ago
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    umm..the answer choices are in format of ( -48,48) and that kind of thing

  6. radar
    • 5 years ago
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    (x-6)=0, x=6 (x+8)=0, x=-8

  7. radar
    • 5 years ago
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    The solution set is x= 6, -8

  8. radar
    • 5 years ago
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    What exactly is asked for the example?

  9. radar
    • 5 years ago
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    Are you working on the "completing the square" method, or factoring or quadratic? for solutions??

  10. anonymous
    • 5 years ago
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    just solution sets. its part of the algebra 2 EOC, so i want to learn how to work them out

  11. radar
    • 5 years ago
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    method I used is called the "factoring method" The quadratic equation was manipulated to equal 0 and then factored. (x+8)(x-6) =0 The reason this works, one or both of the factors has to equal 0 for the results to equal 0. Like, ab=0, then a or b or both equal 0.

  12. anonymous
    • 5 years ago
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    um...im actually not that good at math, just found this site..wish i had found it sooner though. i could have asked for help on my last project

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