## anonymous 5 years ago Find the length of the curve y=((x^6)+8)/16x^2) from x=2 to x=3

1. anonymous

Have you ever heard about arc length?

2. anonymous

yes

3. anonymous

Tell us more, what is the formula?

4. anonymous

arc length=$\int\limits_{a}^{b}1+(dy/dx)^2$

5. anonymous

You're brilliant. What is the derivative of$(x ^{6}+8)/(16x ^{2})$

6. anonymous

$(64x^7+256)/(256x^4)$

7. anonymous

its easy lol , why did u ask

8. anonymous

OK Ramo, one more time pull up the arc length formula and stick this number the derivative where you see dy/dx

9. anonymous

alright after i plug it into the formula to get $\int\limits_{2}^{3}1+((64x^7+256)/(256x^4)^2dx$

10. anonymous

Like my tutor like to say: "You have to clean it up." The square goes through the top and the bottom. The bottom is easy, just plug 256 in calculator and square it. (x^4)^2 just multiply 2x4. The top is, oh well, back to college algebra, sum of two squares.

11. anonymous

awesome thanks so much :)

12. anonymous

Might be a mistake in the numerator. Show us again where you went from original problem to derivative.