anonymous
  • anonymous
Find the length of the curve y=((x^6)+8)/16x^2) from x=2 to x=3
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
Have you ever heard about arc length?
anonymous
  • anonymous
yes
anonymous
  • anonymous
Tell us more, what is the formula?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
arc length=\[\int\limits_{a}^{b}1+(dy/dx)^2\]
anonymous
  • anonymous
You're brilliant. What is the derivative of\[(x ^{6}+8)/(16x ^{2})\]
anonymous
  • anonymous
\[(64x^7+256)/(256x^4)\]
anonymous
  • anonymous
its easy lol , why did u ask
anonymous
  • anonymous
OK Ramo, one more time pull up the arc length formula and stick this number the derivative where you see dy/dx
anonymous
  • anonymous
alright after i plug it into the formula to get \[\int\limits_{2}^{3}1+((64x^7+256)/(256x^4)^2dx\]
anonymous
  • anonymous
Like my tutor like to say: "You have to clean it up." The square goes through the top and the bottom. The bottom is easy, just plug 256 in calculator and square it. (x^4)^2 just multiply 2x4. The top is, oh well, back to college algebra, sum of two squares.
anonymous
  • anonymous
awesome thanks so much :)
anonymous
  • anonymous
Might be a mistake in the numerator. Show us again where you went from original problem to derivative.

Looking for something else?

Not the answer you are looking for? Search for more explanations.