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anonymous

  • 5 years ago

Find the length of the curve y=((x^6)+8)/16x^2) from x=2 to x=3

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  1. anonymous
    • 5 years ago
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    Have you ever heard about arc length?

  2. anonymous
    • 5 years ago
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    yes

  3. anonymous
    • 5 years ago
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    Tell us more, what is the formula?

  4. anonymous
    • 5 years ago
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    arc length=\[\int\limits_{a}^{b}1+(dy/dx)^2\]

  5. anonymous
    • 5 years ago
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    You're brilliant. What is the derivative of\[(x ^{6}+8)/(16x ^{2})\]

  6. anonymous
    • 5 years ago
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    \[(64x^7+256)/(256x^4)\]

  7. anonymous
    • 5 years ago
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    its easy lol , why did u ask

  8. anonymous
    • 5 years ago
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    OK Ramo, one more time pull up the arc length formula and stick this number the derivative where you see dy/dx

  9. anonymous
    • 5 years ago
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    alright after i plug it into the formula to get \[\int\limits_{2}^{3}1+((64x^7+256)/(256x^4)^2dx\]

  10. anonymous
    • 5 years ago
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    Like my tutor like to say: "You have to clean it up." The square goes through the top and the bottom. The bottom is easy, just plug 256 in calculator and square it. (x^4)^2 just multiply 2x4. The top is, oh well, back to college algebra, sum of two squares.

  11. anonymous
    • 5 years ago
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    awesome thanks so much :)

  12. anonymous
    • 5 years ago
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    Might be a mistake in the numerator. Show us again where you went from original problem to derivative.

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