A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

anonymous

  • 5 years ago

Evaluate the indefinite integral: xsin(x^2)dx We are supposed to use U substitution and i substituted everything in but I'm not sure I substituted du correctly.

  • This Question is Closed
  1. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    i would try using u = x^2 .

  2. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    i did and then i made du=xsinsdx but when I put it all together it is not making sense

  3. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    -0.5cos(x^2)

  4. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    let u = x^2. du = 2x dx or x dx = du /2. then the integration will be sin (u) du/2

  5. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    thank you both!

  6. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    welcome ;)

  7. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.