A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 5 years ago
What is the equation of the vertical asymptote of the graph of f(x) = 2 log3(x + 1) 3?
anonymous
 5 years ago
What is the equation of the vertical asymptote of the graph of f(x) = 2 log3(x + 1) 3?

This Question is Closed

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1is that an exponent of 3 on the end?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0It is a sub unit of 3

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I'm trying to make quiz corrections in my math class and I had this one wrong :/

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the answer IS 1 but I don't understand how

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1what were the choices?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1all graphs of logs.... at least normal logs.... never reach zero or negative numbers; any modification of them tends to keep that same trait. when they shift the graph by (x+1) they modify the x component so that it reads x = 1

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Okay, so why would the correct answer choice be 1? I didn't understand it

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0When you say that the graph is shifted by (x + 1), how does the x component GET modified, could you explain that?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1i can try :) all graphs are examined at the origin at (0,0)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1that is the easiest place to examine them up close and personal like; when they are NOT at the origin we have to move them..

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1if the graph is at (x=1)... we write ourselves a note to tell us where we got it from; or rather, how far we had to move it and in what direction to get it to (0,0)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1that way we can put it back when we are done looking at it. if the graph is at x=1; how far and in what direction did we have to move it to get it to the origin?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0we'd move it 1 place to the right, correct?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1that correct; we move the "x" by +1. So we write ourselves a note (x+1); so we can put it back when we are done right?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1suppose x=3 originally; what is our note look like then?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1think about that again; how far and in what direction do we need to move the graph from x=3 to get it to the origin (0)? if we add (+1) to it it gets us to 4... not to zero.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so if x = 3, how far to the origin? that would be 3 units to the left, 3

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1correct :) so our note becomes (x3) to remind ouselves where we got it from.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1so your problem; the log is normally at x = 0 with an Vasymptote of x=0

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1but they got this graph from log(x+1); so where was it originally?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ummm i don't understand it. with the log... would it be x = 1, so that it could move to the right to get to 0?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1thats absolutley correct :) they moved it over (+1) so it was originally at: x=1 .... any answers we get from looking at it from x=0 have to be "adjusted" now...by 1. since the original Vasymp is at 0; the Vasymp has to be adjusted by (1)..... Vasymp of log(x+1) is: x=(01) or simply x=1

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0That makes sense lol! Thank you!!
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.