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anonymous
 5 years ago
d/dt integral from 0,2x of (e^t+2t)dt is?
anonymous
 5 years ago
d/dt integral from 0,2x of (e^t+2t)dt is?

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amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1the derivative of the integral? is that what it says?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1\[\frac{d}{dt}(\int\limits_{0}^{2x} (e^2 +2t)dt)\]

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1derivative and integrals are inverse functions; they cancel each other out...

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1your looking at a graph with a domain of [0,2x] with an equation of: y = e^t + 2t

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1does that make sense?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1is there a selection of answers to choose from?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yeah they are: A) e^2x+4x B)e^2x+4x1 C) e^2x+4x^21 D)2e^2x+4x E)2e^2x+8x

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1they appear to be using the (2x) as the variable; so my best guess is [A]. e^(2x) + 2(2x) = e^(2x) + 4x

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0In the answer sheet it says E, but I have no idea how they got it.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1lol.....[E]? yeah, got no idea how theyd get that one....

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0lol.. i got the first part but idk how they got 8x

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1we can try this; go ahead and integrate first to: e^(t) + t ; now fill in the interval [0,2x] e^(2x) + 2x e^(0) D{t} [e(2x) +2x  1] 2e^(2x) + 2 ??

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1....integrate the 2t up to t^2 :) typoed in my head lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0nvm i think i got it... you know how ur supposed to find the derivative and since there is no 2 you add it. Then if you distribute it you're gonna get 2e^t+4t. and then when i plug in the 2x i get E

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0does that sound about right?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1e^(t) + t^2 ; now fill in the interval [0,2x] e^(2x) + (2x)^2 e^(0) D{t} [e(2x) +4x^2  1] 2e^(2x) + 8x

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1this appears to be the logic :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yay :) Thank you!! lol
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