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anonymous

  • 5 years ago

how to solve using synthetic division.... (2x^5+2x^4+4x^3-2x^3-4x+3)/x+2

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  1. amistre64
    • 5 years ago
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    2x^2 right? thats a typo?

  2. amistre64
    • 5 years ago
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    (x+2); x = -2 -2| 2 +2 +4 -2 -4 +3 0 -4 +4 -16 +36 -64 --------------------- 2 -2 +8 -18 +32 -61

  3. anonymous
    • 5 years ago
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    yea thats suppose to be 4x^3-2x^2

  4. amistre64
    • 5 years ago
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    -61 2x^4 -2x^3 +8x^2 -18x +32 + ----- (x+2)

  5. anonymous
    • 5 years ago
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    amistre64 =right!

  6. amistre64
    • 5 years ago
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    yay!! .... i got one with out a typo lol

  7. amistre64
    • 5 years ago
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    do you see how I got it mcoley?

  8. anonymous
    • 5 years ago
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    lol wait okay im lost which is the answer lol im trying to follow i confused myself

  9. amistre64
    • 5 years ago
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    the first one is synthetic division to get all the "coefficiants" and a remainder: (x+2); x = -2 -2| 2 +2 +4 -2 -4 +3 0 -4 +4 -16 +36 -64 --------------------- 2 -2 +8 -18 +32 -61 Next we apply these coeefecients and the remainder into their normal form of: -61 2x^4 -2x^3 +8x^2 -18x +32 + ----- (x+2) It all depends on what format the "answer" is looking for really.

  10. amistre64
    • 5 years ago
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    i should first ask if you understand how we did the synthetic division... so do you?

  11. anonymous
    • 5 years ago
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    I see what your doing yea.. lol i get it

  12. amistre64
    • 5 years ago
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    good:)

  13. anonymous
    • 5 years ago
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    I was trying to do it myself n i must have miscalculated

  14. amistre64
    • 5 years ago
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    lol.... i miscalculate alot too :)

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