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anonymous
 5 years ago
how to solve using synthetic division....
(2x^5+2x^4+4x^32x^34x+3)/x+2
anonymous
 5 years ago
how to solve using synthetic division.... (2x^5+2x^4+4x^32x^34x+3)/x+2

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amistre64
 5 years ago
Best ResponseYou've already chosen the best response.02x^2 right? thats a typo?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0(x+2); x = 2 2 2 +2 +4 2 4 +3 0 4 +4 16 +36 64  2 2 +8 18 +32 61

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yea thats suppose to be 4x^32x^2

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.061 2x^4 2x^3 +8x^2 18x +32 +  (x+2)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0yay!! .... i got one with out a typo lol

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0do you see how I got it mcoley?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0lol wait okay im lost which is the answer lol im trying to follow i confused myself

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0the first one is synthetic division to get all the "coefficiants" and a remainder: (x+2); x = 2 2 2 +2 +4 2 4 +3 0 4 +4 16 +36 64  2 2 +8 18 +32 61 Next we apply these coeefecients and the remainder into their normal form of: 61 2x^4 2x^3 +8x^2 18x +32 +  (x+2) It all depends on what format the "answer" is looking for really.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0i should first ask if you understand how we did the synthetic division... so do you?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I see what your doing yea.. lol i get it

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I was trying to do it myself n i must have miscalculated

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0lol.... i miscalculate alot too :)
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