## anonymous 5 years ago Please! help me check my answe,do even only, 2) Degree 4) GCF 6) Polynomial 8) Simplify 10) Synthetisc dubtitution

1. anonymous
2. anonymous

sorry subtitution not dubtitution

8 = 8 10=4

4. anonymous

not solve, just fill the word in the blank

5. anonymous

I need check my answer if I correct

8, Simplify 4, synthetic division

seems the choices are too restricted!!

8. anonymous

number 10 Synthetisc dubtitution ?

Not for sure, have you googled those words?

10. anonymous

no

11. anonymous

you have time look another problem?

I don't see any on the list that would match "degree"

I may be of help, what is the probllem?

14. anonymous

you want me sent you a lesion degree?

the degree of an equation depends on the highest exponent of the variable, and there was nothing like that on the list. What is the next problem?

16. anonymous

I have looked it over. Here is what I have come up with: Let x = longer leg Let y= shorter leg then 24-(x+y)= hypotenuse You with me so far. Ask question now about what I have set up for solving this problem.

We are told the following: 3x-2y=24-(x+y)+3 Do you see where that come from?

19. anonymous

P: x+y+z=24 The given: (3*x)-(2*y)=h+2 I know from here ,But I don't know next

20. anonymous

sorry z for hypotenuse The given: (3*x)-(2*y)=z+2

O.k I put 3 where it should be 2, my equation should be 3x-2y = 24-x-y +2

then we would have 4x+3y = 26 That is an equation with two unknowns we need to make another equartion. But first need to fix another mistake. 4x-y=26 Do you see why 4x-y=26 cm????

23. anonymous

yes I see

This means y=4x-26. Problem says it is a right triangle we know that by pythagorem theorem hypotenuse is equal to the square root of the sum of the legs squared or$\sqrt{x ^{2}+y ^{2}}$

we substitute for y and get this: $hyp=\sqrt{x ^{2}+(4x-26)^{2}}$ We also know that the hypotenuse is equal to 24-x-y substituting for y we now have hypotnuse=24-x-(4x-26) hyp=-5x+50 $-5x+50=\sqrt{x ^{2}+(4x-26)^{2}}$Now we have an equality with one unknown

The radical should extend completely across$-5x+50=\sqrt{x ^{2}-(16x ^{2}-208x+676}$

27. anonymous

Arte you still there?

28. anonymous

From here I just solve for x?

square both sides of the equation $25x ^{2}-500x+2500=x ^{2}-16x ^{2}-208x+676$ This thing keeps getting bigger and bigger!!!$40x ^{2}-292x+1824=0$ A quadratic that should be solvable lol

30. anonymous

Ok. thank I can do from now

You can divide by 4 and get $10x ^{2}-73x+456=0$

32. anonymous

I have one more very quick, can you show me how to write faction on the bottom of the chat, I keep play but I can do it.

I don't know how to write frac on the equation line, if you google latex you will find the math languate they use here.

34. anonymous

on the bottom of the chat window

35. anonymous

it say Equation

36. anonymous

I see every people write fraction

loki showed me how, but I forget, if you look at "latex" it will explain it.

38. anonymous

it Ok I will ask pepole around, thank you for spend time solve my problem

39. anonymous

I have to go now bye

Ok, somewhere there is an error in the solution as the root is a complex value. I will loolk it over and see where it went wrong.

There were errors, the final quadratic should appear as:$8x ^{2}-292x+1824=0$ When solved, you will find x=8 (longer leg) substitute x in the y=4x-26=32-26=y y=6 cm (shorter leg) 24-6-8=10cm the hypotenuse It checks out.