Use chain rule to find dy/dx for the given value of x.
y+ (u-1/u+1)^1/2
u=sqrt x-1; for x=34/9

Use chain rule to find dy/dx for the given value of x.
y+ (u-1/u+1)^1/2
u=sqrt x-1; for x=34/9

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first step I get
1/2 (u-1/u+1)^-1/2
not sure what to do next. I am brain dead at the moment.

what was original function
did you replace dx with du
du = dx/2sqrt(x-1)

sorry i think im mistaken, ignore what i just said
but you will use du

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