anonymous
  • anonymous
can some one help me find the the local extrema for 2x^5-5x^2+1
Mathematics
schrodinger
  • schrodinger
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amistre64
  • amistre64
take the derivative and find the zeros
amistre64
  • amistre64
D(2x^5 -5x^2 +1) = 10x^4 -10x 10x^4 = 10x x^4 = x ...... mu guess is at 1 and -1
amistre64
  • amistre64
x(x^3 - 1) (10)(x)(x-1)(x^2 +x +1) or quite possibly at: x = 0, 1

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amistre64
  • amistre64
check 2nd derivative for concavity...
amistre64
  • amistre64
or plug these x value sinto the original and see whats bigger :)
amistre64
  • amistre64
f(0) = 1 f(1) = -2
amistre64
  • amistre64
http://www.wolframalpha.com/input/?i=2x%5E5-5x%5E2%2B1 gives you a good picture of it
anonymous
  • anonymous
awesome thank you very much

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