anonymous
  • anonymous
How do i factor this? what is the method to determine the factors 6b^2+4a-8b-3ab
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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amistre64
  • amistre64
grouping seems most likely
amistre64
  • amistre64
6b^2+4a-8b-3ab (-3ab-8b) + (6b^2+4a) -b(3a+8) + 2(3b^2 +2a)..... perhaps its: (6b^2-3ab)+(4a-8b) 3b(2b-a) +4(a-2b) thats better; now factor a -1 out of the first thing
amistre64
  • amistre64
-3b(a-2b) +4(a-2b) = (a-2b)(4a-3b)

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amistre64
  • amistre64
(a-2b)(4-3b)...... typoed it :)
myininaya
  • myininaya
i'm afraid he's one
myininaya
  • myininaya
right*
anonymous
  • anonymous
(4-3b) isnt one of my options, i have 4+3b
myininaya
  • myininaya
any other options
amistre64
  • amistre64
then they factored out a -1 from the other side itll look like this... 3b(2b-a) +4(a-2b) 3b(2b-a) -4(2b-a) (2b-a)(3b-4)......hmmm
amistre64
  • amistre64
(2b-a)(3b+4)
amistre64
  • amistre64
(2b-a)(4+3b)...... is also a way of writng it
anonymous
  • anonymous
(8+3a), (2a+3b^2), (a-2b), (4+3b), (a+2b)
myininaya
  • myininaya
or you could just multiply by (-1)(-1) (-1)(a-2b)(-1)(4-3b) (2b-a)(3b-4)
amistre64
  • amistre64
(a-2b) is possible; and (4+3b) is possible; just not at the same time :)
amistre64
  • amistre64
(2b-a)(4+3b) 8b +6b^2 -4a -3ab... which aint original; so that aint it
amistre64
  • amistre64
(a-2b)(4-3b) 4a -3ab -8b +6b^2...is the original; so go with that. (a-2b)
anonymous
  • anonymous
ok i will give that a shot. Thanks a lot

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