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anonymous
 5 years ago
How do i factor this? what is the method to determine the factors
6b^2+4a8b3ab
anonymous
 5 years ago
How do i factor this? what is the method to determine the factors 6b^2+4a8b3ab

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amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1grouping seems most likely

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.16b^2+4a8b3ab (3ab8b) + (6b^2+4a) b(3a+8) + 2(3b^2 +2a)..... perhaps its: (6b^23ab)+(4a8b) 3b(2ba) +4(a2b) thats better; now factor a 1 out of the first thing

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.13b(a2b) +4(a2b) = (a2b)(4a3b)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1(a2b)(43b)...... typoed it :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0(43b) isnt one of my options, i have 4+3b

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1then they factored out a 1 from the other side itll look like this... 3b(2ba) +4(a2b) 3b(2ba) 4(2ba) (2ba)(3b4)......hmmm

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1(2ba)(4+3b)...... is also a way of writng it

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0(8+3a), (2a+3b^2), (a2b), (4+3b), (a+2b)

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0or you could just multiply by (1)(1) (1)(a2b)(1)(43b) (2ba)(3b4)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1(a2b) is possible; and (4+3b) is possible; just not at the same time :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1(2ba)(4+3b) 8b +6b^2 4a 3ab... which aint original; so that aint it

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1(a2b)(43b) 4a 3ab 8b +6b^2...is the original; so go with that. (a2b)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok i will give that a shot. Thanks a lot
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