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anonymous

  • 5 years ago

If a car is travelling 80 miles per hour on a slippery road, then its stopping distance D in feet can be calculated by D=(6400/80)*(1/x), where x is teh coefficient of friction between the tires and road and 0<x< or equal to 1. multiply and simplify the formula for D and Compare the stopping distance on an icy road with x=0.2 and on dry pavement with x=0.8. so D=? the stopping distance on an icy road is ?? feet.(round to the nearest whole number as needed) the stopping distance on dry pavement is?? ft. When a car is moving at 80 miles per hour, the stopping distance on dry pavement is__ of

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  1. dumbcow
    • 5 years ago
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    D = 80/x you are just reducing x=.2 -> D = 80*5=400 x=.8 -> D=80*(5/4) = 100

  2. anonymous
    • 5 years ago
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    what about if teh car is moving at 80 miles per hour the stopping distance on dry pavement is __ of the stopping distance of an icy road?? (type as an integer or simplified fraction)

  3. anonymous
    • 5 years ago
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    I really appreciate your help

  4. dumbcow
    • 5 years ago
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    i already answered that....we are already assuming car is going 80 mph its already factored into equation for D

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