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anonymous

  • 5 years ago

find the quotient: 25c^4+20c^3 ------------ 5c

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  1. anonymous
    • 5 years ago
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    when you divide with the same base you subtract the exponents 5c-c has an exponent of 1

  2. anonymous
    • 5 years ago
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    25c^4/5c^1=5c^3 and 20c^3/5c^1=4c^2

  3. anonymous
    • 5 years ago
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    so final answer is 5c^3+4c^2...do you understand?

  4. anonymous
    • 5 years ago
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    yea thanks

  5. anonymous
    • 5 years ago
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    you're welcome...anything else?

  6. anonymous
    • 5 years ago
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    yea is this right 63b^4-9b^3 --------- 9b = -7b^3+b^2

  7. anonymous
    • 5 years ago
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    yes or 7b^3-b^2

  8. anonymous
    • 5 years ago
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    good job!

  9. anonymous
    • 5 years ago
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    thanks for ur help

  10. anonymous
    • 5 years ago
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    u there?

  11. anonymous
    • 5 years ago
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    -21w^4-21w^3 ------------- 7w = -3w^3-3w^2 is this right?

  12. anonymous
    • 5 years ago
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    i thnk i messed up it should be a + not - right?

  13. anonymous
    • 5 years ago
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    sorry

  14. anonymous
    • 5 years ago
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    you are correct!

  15. anonymous
    • 5 years ago
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    u no much bout inequalities

  16. anonymous
    • 5 years ago
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    yes

  17. anonymous
    • 5 years ago
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    can u help me

  18. anonymous
    • 5 years ago
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    I will try

  19. anonymous
    • 5 years ago
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    y<x=2 \[y \ge5\]

  20. anonymous
    • 5 years ago
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    y<x+2 sorry

  21. anonymous
    • 5 years ago
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    n second one together

  22. anonymous
    • 5 years ago
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    have to graph it too

  23. anonymous
    • 5 years ago
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    do you know how to graph using y=mx+b with y-int and slope

  24. anonymous
    • 5 years ago
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    n second one together

  25. anonymous
    • 5 years ago
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    yea kind of confusing

  26. anonymous
    • 5 years ago
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    ok second inequality is a horizontal line passing throug (0, 5) shading above the solid line

  27. anonymous
    • 5 years ago
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    first one is a dotted line using y=mx+b the y-int(b=2) you start at (0,2) and use the slope(m-coefficient of x) which is 1/1 so from (0,2) rise 1(up) run 1(right) to get second point

  28. anonymous
    • 5 years ago
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    shading should include (0,0) so to the right of the diagonal line

  29. anonymous
    • 5 years ago
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    the solution is the area where the shading overlaps-top right area similar to less than shape : )

  30. anonymous
    • 5 years ago
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    did you get lost?

  31. anonymous
    • 5 years ago
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    yeah does it look like this kind of lol the direction \ ---------------- \

  32. anonymous
    • 5 years ago
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    the diagonal lines is going up from left to right bc the slope is positive

  33. anonymous
    • 5 years ago
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    like this lol / --------------------- / /

  34. anonymous
    • 5 years ago
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    so lower right is shaded right

  35. anonymous
    • 5 years ago
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  36. anonymous
    • 5 years ago
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    top right---see pic but diagonal should be dotted

  37. anonymous
    • 5 years ago
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    k thas what i have but had top line dotted too lol appreciate ur patience:)

  38. anonymous
    • 5 years ago
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  39. anonymous
    • 5 years ago
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    dotted line for greater than or less than solid when you have equal sign with the inequality

  40. anonymous
    • 5 years ago
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    love helping students in math so I have great patience : )

  41. anonymous
    • 5 years ago
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    y>4 \[x \le2\] up two straight across on fourth line

  42. anonymous
    • 5 years ago
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    2 is diagonal right dotted line

  43. anonymous
    • 5 years ago
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    y>4 is dotted line through (0,4) shading above the line because when you substitute (0,0) into the inequality, 0>4 is not true so shading should not include test point (0,0)

  44. anonymous
    • 5 years ago
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    2nd one is vertical solid line passing through (2,0) shade to the left because 0 is less than or equal to 2

  45. anonymous
    • 5 years ago
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    solution area is in top left right angle

  46. anonymous
    • 5 years ago
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    I think i got it right i would post pic but when other viewer clicks it opens blank dont no why.

  47. anonymous
    • 5 years ago
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    what is your number i can send you a text with pic

  48. anonymous
    • 5 years ago
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    nevermind I'll send to my email and post in here

  49. anonymous
    • 5 years ago
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    but anyways thank you so much.... had to take a plato class fot algebra. i graduate may 26, this month so this will be my last open study. thanks again

  50. anonymous
    • 5 years ago
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    CONGRATS!!! Do you need me to post pic

  51. anonymous
    • 5 years ago
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    yea please

  52. anonymous
    • 5 years ago
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    rsanchz68@gmail.com

  53. anonymous
    • 5 years ago
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  54. anonymous
    • 5 years ago
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    you can email me if you need any other math help else brishundra@yahoo.com

  55. anonymous
    • 5 years ago
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    where is diagonal line at

  56. anonymous
    • 5 years ago
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    no diagonal line is this one becuase y= is horizontal x=is vertical

  57. anonymous
    • 5 years ago
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    so same is true for inequality graphs..graph them just like y= or x=

  58. anonymous
    • 5 years ago
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    o yeah k got ur email thanks

  59. anonymous
    • 5 years ago
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    welcome!

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