anonymous
  • anonymous
find the quotient: 25c^4+20c^3 ------------ 5c
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
when you divide with the same base you subtract the exponents 5c-c has an exponent of 1
anonymous
  • anonymous
25c^4/5c^1=5c^3 and 20c^3/5c^1=4c^2
anonymous
  • anonymous
so final answer is 5c^3+4c^2...do you understand?

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anonymous
  • anonymous
yea thanks
anonymous
  • anonymous
you're welcome...anything else?
anonymous
  • anonymous
yea is this right 63b^4-9b^3 --------- 9b = -7b^3+b^2
anonymous
  • anonymous
yes or 7b^3-b^2
anonymous
  • anonymous
good job!
anonymous
  • anonymous
thanks for ur help
anonymous
  • anonymous
u there?
anonymous
  • anonymous
-21w^4-21w^3 ------------- 7w = -3w^3-3w^2 is this right?
anonymous
  • anonymous
i thnk i messed up it should be a + not - right?
anonymous
  • anonymous
sorry
anonymous
  • anonymous
you are correct!
anonymous
  • anonymous
u no much bout inequalities
anonymous
  • anonymous
yes
anonymous
  • anonymous
can u help me
anonymous
  • anonymous
I will try
anonymous
  • anonymous
y
anonymous
  • anonymous
y
anonymous
  • anonymous
n second one together
anonymous
  • anonymous
have to graph it too
anonymous
  • anonymous
do you know how to graph using y=mx+b with y-int and slope
anonymous
  • anonymous
n second one together
anonymous
  • anonymous
yea kind of confusing
anonymous
  • anonymous
ok second inequality is a horizontal line passing throug (0, 5) shading above the solid line
anonymous
  • anonymous
first one is a dotted line using y=mx+b the y-int(b=2) you start at (0,2) and use the slope(m-coefficient of x) which is 1/1 so from (0,2) rise 1(up) run 1(right) to get second point
anonymous
  • anonymous
shading should include (0,0) so to the right of the diagonal line
anonymous
  • anonymous
the solution is the area where the shading overlaps-top right area similar to less than shape : )
anonymous
  • anonymous
did you get lost?
anonymous
  • anonymous
yeah does it look like this kind of lol the direction \ ---------------- \
anonymous
  • anonymous
the diagonal lines is going up from left to right bc the slope is positive
anonymous
  • anonymous
like this lol / --------------------- / /
anonymous
  • anonymous
so lower right is shaded right
anonymous
  • anonymous
1 Attachment
anonymous
  • anonymous
top right---see pic but diagonal should be dotted
anonymous
  • anonymous
k thas what i have but had top line dotted too lol appreciate ur patience:)
anonymous
  • anonymous
1 Attachment
anonymous
  • anonymous
dotted line for greater than or less than solid when you have equal sign with the inequality
anonymous
  • anonymous
love helping students in math so I have great patience : )
anonymous
  • anonymous
y>4 \[x \le2\] up two straight across on fourth line
anonymous
  • anonymous
2 is diagonal right dotted line
anonymous
  • anonymous
y>4 is dotted line through (0,4) shading above the line because when you substitute (0,0) into the inequality, 0>4 is not true so shading should not include test point (0,0)
anonymous
  • anonymous
2nd one is vertical solid line passing through (2,0) shade to the left because 0 is less than or equal to 2
anonymous
  • anonymous
solution area is in top left right angle
anonymous
  • anonymous
I think i got it right i would post pic but when other viewer clicks it opens blank dont no why.
anonymous
  • anonymous
what is your number i can send you a text with pic
anonymous
  • anonymous
nevermind I'll send to my email and post in here
anonymous
  • anonymous
but anyways thank you so much.... had to take a plato class fot algebra. i graduate may 26, this month so this will be my last open study. thanks again
anonymous
  • anonymous
CONGRATS!!! Do you need me to post pic
anonymous
  • anonymous
yea please
anonymous
  • anonymous
anonymous
  • anonymous
1 Attachment
anonymous
  • anonymous
you can email me if you need any other math help else brishundra@yahoo.com
anonymous
  • anonymous
where is diagonal line at
anonymous
  • anonymous
no diagonal line is this one becuase y= is horizontal x=is vertical
anonymous
  • anonymous
so same is true for inequality graphs..graph them just like y= or x=
anonymous
  • anonymous
o yeah k got ur email thanks
anonymous
  • anonymous
welcome!

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