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when you divide with the same base you subtract the exponents 5c-c has an exponent of 1
25c^4/5c^1=5c^3 and 20c^3/5c^1=4c^2
so final answer is 5c^3+4c^2...do you understand?
you're welcome...anything else?
yea is this right 63b^4-9b^3 --------- 9b = -7b^3+b^2
yes or 7b^3-b^2
thanks for ur help
-21w^4-21w^3 ------------- 7w = -3w^3-3w^2 is this right?
i thnk i messed up it should be a + not - right?
you are correct!
u no much bout inequalities
can u help me
I will try
n second one together
have to graph it too
do you know how to graph using y=mx+b with y-int and slope
n second one together
yea kind of confusing
ok second inequality is a horizontal line passing throug (0, 5) shading above the solid line
first one is a dotted line using y=mx+b the y-int(b=2) you start at (0,2) and use the slope(m-coefficient of x) which is 1/1 so from (0,2) rise 1(up) run 1(right) to get second point
shading should include (0,0) so to the right of the diagonal line
the solution is the area where the shading overlaps-top right area similar to less than shape : )
did you get lost?
yeah does it look like this kind of lol the direction \ ---------------- \
the diagonal lines is going up from left to right bc the slope is positive
like this lol / --------------------- / /
so lower right is shaded right
top right---see pic but diagonal should be dotted
k thas what i have but had top line dotted too lol appreciate ur patience:)
dotted line for greater than or less than solid when you have equal sign with the inequality
love helping students in math so I have great patience : )
y>4 \[x \le2\] up two straight across on fourth line
2 is diagonal right dotted line
y>4 is dotted line through (0,4) shading above the line because when you substitute (0,0) into the inequality, 0>4 is not true so shading should not include test point (0,0)
2nd one is vertical solid line passing through (2,0) shade to the left because 0 is less than or equal to 2
solution area is in top left right angle
I think i got it right i would post pic but when other viewer clicks it opens blank dont no why.
what is your number i can send you a text with pic
nevermind I'll send to my email and post in here
but anyways thank you so much.... had to take a plato class fot algebra. i graduate may 26, this month so this will be my last open study. thanks again
CONGRATS!!! Do you need me to post pic
where is diagonal line at
no diagonal line is this one becuase y= is horizontal x=is vertical
so same is true for inequality graphs..graph them just like y= or x=
o yeah k got ur email thanks