anonymous
  • anonymous
The angle of elevation to the top of the radio atenna on the top of a building is 53.4 degrees. After moving 200 feet closer to the building, the angle of elevation is 63.4 degrees. Find the height of the building if the height of the atenna is 189 feet. Please HELP!
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
amistre64
  • amistre64
1 Attachment
amistre64
  • amistre64
is the height of the antennea AT 189 ft? or is the antennea 189FT tall?
anonymous
  • anonymous
imaging right triangle, where is the h (hight of the building) is one side of the triangle + 189 ft for antenna now if alpha= angle 53.4 and beta= angles 63.4 on a bottom (other side of the right triangle) - length x will become (x-200) after it's moved so, tan alpha = (h+189)/x tan beta=(h+189)/(x-200) you know angles; you have a system of two ew with two variables - should be able to solve it. let me know if there is a problem

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
Actually the height of the antenna is 180ft. Sorry, my mistake!
anonymous
  • anonymous
just input 180 instead of 189 in the above. should work the same
amistre64
  • amistre64
..... antennea = 180? ...... or top of antennea is at 180' ?
anonymous
  • anonymous
Oh and the antenna is 180ft tall.
amistre64
  • amistre64
the antennea is bigger than a football field at the moment
anonymous
  • anonymous
Haha.
amistre64
  • amistre64
tan(53.4) = (180+h)/(200+d) tan(63.4) = (180+h)/(d)
amistre64
  • amistre64
d = (180+h)/tan(63.4) tan(53.4) = (180+h)/(200+[(180+h)/tan(63.4)]) tan(53.4.) = (180+h)/[(tan(63.4)180 + 180 + h)/tan(63.4)]
amistre64
  • amistre64
lets clean this up with a = tan(53.4) and b=tan(63.4) a = (180+h)/[(200b + 180 + h)/b] 180b + hb a = --------------- 200b + 180 + h
amistre64
  • amistre64
... see if iniks way works better lol
amistre64
  • amistre64
1.3465 = (180+h)/(200+[(180+h)/1.9969) 1.3465 = (180+h)/[(579.392+h)/1.9969]) 2.69 ---------- = 180 + h 579.392 +h 2.69 = (180 +h) (579.392 +h) 2.69 = h^2 +759.392h +104290.56 ...... this is messy :)
anonymous
  • anonymous
Thank you SO much!

Looking for something else?

Not the answer you are looking for? Search for more explanations.