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anonymous
 5 years ago
amistre, need you for about a minute
anonymous
 5 years ago
amistre, need you for about a minute

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0homogeneous vs. nonhomogeneous recap

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1ack!!... lol what do we need to recap :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0a was not homogeneouss

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1recursion equations.....

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0On worksheet 12A, part a) is nonhomogeneous. I've pasted in below the definition of the terminology for homogeneous. I think that what you are missing is that they are implying, but not directly saying, that you put you x terms on the left, and your nonx terms on the right. So the equation in a) should be analyzed as xn+1 +xn1 =  n^2, or more directly matching the expression highlighted in yellow below, we would write: xn+1  (1)xn1 = n^2 Clearly the nonx term, n^2 is not worth zero.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1ok... 1a or 2a? 2a was definanlty not homogenous...

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1the only thing that is squared to get zero is zero.... right?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1and I agree that n^2 would definantly not be 0...all the time ;)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1X{n+1} + n^2 + X{n1} = 0 that n^2 makes me think its not linear; or do we only look at the X{..} parts for that?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0only have c as linear

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so would b also be nonhom

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1well, then X{...} parts all come to one side and we are left with 0 over there for b0 right?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1X{n+1}  (pi)X{n} " (2^2)X{n} = 0 right?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1is that spoosed to be 2 [X{n}]^2?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0that was original rationale but when I emailed him that I got confused by his response

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1what was his respone?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0No, you can't get the right side to zero by transforming it, causing all >>of >>the constants to go to the left side.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1lol...isnt that what the book does? the material says to put it all to the other side and equate it to zero :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1what aint attached to an X{...} stays put

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1id say yes, but your material is not easy to parse :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1you need to find help with recurrsion equations; and see if anyone can aid you in that way :) calling them difference equations is like speaking a foriegn language..

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I've bee reading about them all weekend and the name does throw people off...

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1i would say that d is left with a 1/2 on one side..... im guesing nonhomo

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok bc cand divide to move yn and have 1/2 not 0 on the right side

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1with b you should subtract everything over there becasue they involve X{....} leaving you with 0

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes so I have b only homo

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1as far as I can tell; yes :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1wish i could be more confident on those; but they seem to elude me ;)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no problem,,,thanks sooooo much for all of your help!!!!!!
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