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Mathematics
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homogeneous vs. non-homogeneous recap
ack!!... lol what do we need to recap :)
a was not homogeneouss

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Other answers:

recursion equations.....
On worksheet 12A, part a) is non-homogeneous. I've pasted in below the definition of the terminology for homogeneous. I think that what you are missing is that they are implying, but not directly saying, that you put you x terms on the left, and your non-x terms on the right. So the equation in a) should be analyzed as xn+1 +xn-1 = - n^2, or more directly matching the expression highlighted in yellow below, we would write: xn+1 - (-1)xn-1 = -n^2 Clearly the non-x term, -n^2 is not worth zero.
ok... 1a or 2a? 2a was definanlty not homogenous...
1 Attachment
number 1 had 4 parts
the only thing that is squared to get zero is zero.... right?
and I agree that -n^2 would definantly not be 0...all the time ;)
yes
1 Attachment
X{n+1} + n^2 + X{n-1} = 0 that n^2 makes me think its not linear; or do we only look at the X{..} parts for that?
only have c as linear
so would b also be nonhom
well, then X{...} parts all come to one side and we are left with 0 over there for b0 right?
yes
X{n+1} - (pi)X{n} " (2^2)X{n} = 0 right?
is that spoosed to be 2 [X{n}]^2?
that was original rationale but when I emailed him that I got confused by his response
yes
what was his respone?
No, you can't get the right side to zero by transforming it, causing all >>of >>the constants to go to the left side.
lol...isnt that what the book does? the material says to put it all to the other side and equate it to zero :)
what aint attached to an X{...} stays put
so b is homo
id say yes, but your material is not easy to parse :)
you need to find help with recurrsion equations; and see if anyone can aid you in that way :) calling them difference equations is like speaking a foriegn language..
c is nonhomo d???
I've bee reading about them all weekend and the name does throw people off...
d homo?
i would say that d is left with a 1/2 on one side..... im guesing nonhomo
ok bc cand divide to move yn and have 1/2 not 0 on the right side
with b you should subtract everything over there becasue they involve X{....} leaving you with 0
yes so I have b only homo
as far as I can tell; yes :)
ok thanks!
wish i could be more confident on those; but they seem to elude me ;)
no problem,,,thanks sooooo much for all of your help!!!!!!

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