amistre, need you for about a minute

- anonymous

amistre, need you for about a minute

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- anonymous

homogeneous vs. non-homogeneous recap

- amistre64

ack!!... lol what do we need to recap :)

- anonymous

a was not homogeneouss

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## More answers

- amistre64

recursion equations.....

- anonymous

On worksheet 12A, part a) is non-homogeneous. I've pasted in below the definition of the terminology for homogeneous. I think that what you are missing is that they are implying, but not directly saying, that you put you x terms on the left, and your non-x terms on the right. So the equation in a) should be analyzed as
xn+1 +xn-1 = - n^2, or more directly matching the expression highlighted in yellow below, we would write:
xn+1 - (-1)xn-1 = -n^2
Clearly the non-x term, -n^2 is not worth zero.

- amistre64

ok... 1a or 2a? 2a was definanlty not homogenous...

- anonymous

##### 1 Attachment

- anonymous

number 1 had 4 parts

- amistre64

the only thing that is squared to get zero is zero.... right?

- amistre64

and I agree that -n^2 would definantly not be 0...all the time ;)

- anonymous

yes

##### 1 Attachment

- amistre64

X{n+1} + n^2 + X{n-1} = 0
that n^2 makes me think its not linear; or do we only look at the X{..} parts for that?

- anonymous

only have c as linear

- anonymous

so would b also be nonhom

- amistre64

well, then X{...} parts all come to one side and we are left with 0 over there for b0 right?

- anonymous

yes

- amistre64

X{n+1} - (pi)X{n} " (2^2)X{n} = 0 right?

- amistre64

is that spoosed to be 2 [X{n}]^2?

- anonymous

that was original rationale but when I emailed him that I got confused by his response

- anonymous

yes

- amistre64

what was his respone?

- anonymous

No, you can't get the right side to zero by transforming it, causing all
>>of
>>the constants to go to the left side.

- amistre64

lol...isnt that what the book does? the material says to put it all to the other side and equate it to zero :)

- amistre64

what aint attached to an X{...} stays put

- anonymous

so b is homo

- amistre64

id say yes, but your material is not easy to parse :)

- amistre64

you need to find help with recurrsion equations; and see if anyone can aid you in that way :) calling them difference equations is like speaking a foriegn language..

- anonymous

c is nonhomo d???

- anonymous

I've bee reading about them all weekend and the name does throw people off...

- anonymous

d homo?

- amistre64

i would say that d is left with a 1/2 on one side..... im guesing nonhomo

- anonymous

ok bc cand divide to move yn and have 1/2 not 0 on the right side

- amistre64

with b you should subtract everything over there becasue they involve X{....} leaving you with 0

- anonymous

yes so I have b only homo

- amistre64

as far as I can tell; yes :)

- anonymous

ok thanks!

- amistre64

wish i could be more confident on those; but they seem to elude me ;)

- anonymous

no problem,,,thanks sooooo much for all of your help!!!!!!

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