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suppose you have a coin. what is the probability of it landing heads?
ok i know the answer to the question is .0313, anyone know how?
see if 1/32 is 0.0313
yeah how did you get 32
the probability of having a girl is 1/2. so the probability of having a boy is 1/2. in a family of 5 children, all are boys. i.e, there are no girls. so the parents had five boys consecutively. so the probability of having 5 boys in a row is 1/2 times 1/2 times 1/2 times 1/2 times 1/2
ok thanks, know how to get this one? a bag contains 6 cherry, 3 orange, and 2 lemon candies. you reach in and take 3 pieces of candy at random. find the probability you with pick 2 cherry and 1 lemon
yes, but do you want the answer or do you want to learn how to do this?
learn how, i know the answer
okay. so suppose you have 2 candies in the bag. one is lemon and one is grape. what is the probability that you will pick the lemon candy?
okay good. suppose you have three candies. one lemon one grape and one cherry. what is the probability you pick the lemon ?
okay good. suppose you have three candies, two lemon and one cherry. what is the probability you pick a lemon candy?
okay very good. now you have 6 cherry, 3 lemon and 2 grape candies. what is the probability that you pick one cherry candy?
okay very good. now, you have already picked one candy. so there are ten candies left. 5 cherry, 3 lemon and 2 grape. what is the probability that you pick a cherry candy?
5/10 so 1/2
yes, good. now there are 9 candies left. 4 cherry, 3 lemon and 2 grape. what is the probability that you pick a lemon candy?
3/9, and then you multiply right? thats how i tried to solve the original one but i got the wrong answer
yes, so the probability that you pick 2 cherry candies in a row and then one lemon candy is 6/11 times 1/2 times 1/3.
for 6 cherry, 3 orange, and 2 lemon; the prob of 2 cherry and 1 lemon: answer is supposed to be .1818
solving its that way gets .0909
the question says there are only 2 lemon candies and there are 3 orange candies. so for the third try, you pick a lemon candy out of 9 candies, the probability of that is 2/9 so the answer should be 6/11 times 1/2 times 2/9
yeah i can do that and get .0606; but the book says the answer is supposed to be .1818
thats why im confused
wait, is that supposed to be in that order?
it says at random
yeah it says random, but is the expected answer 1 cherry then 1 cherry then 1 lemon or is it that you pick three candies and you end up with 2 cherries and 1 lemon?
okay looks like you are not reaching in three times. you just reach in once and take three candies.
it says "you reach in and take 3 pieces of candy at random"
do you know how to figure it out that way?
yeah. you have to do it the following way: 6C2/11C3 times 2C1/11C3
have you done permutations and combinations? BTW ignore my answer. that is incorrect. I will calculate the correct answer and post it here.
my teacher gave us problems to do but never taught us how, but yes we are supposed to be doing permutations and combinations. any quick formulas i can jot down for the test?
The answer is 6C2 times 2C1 divided by 11C3
ohh ok that makes sense! thanks!
so that is 15 times 2 divided by 165 = 30/165 = 0.181818181
you dont know how to do combinations?
then how did it make sense to you?
she showed us the calculator commands for the c but didnt show us what it was for, now i know
read through that and ask me if you have doubts.
thanks soo much!
probability in poker, a flush in any suit?
what is your question?