a family has 5 children. the probability of having a girl is 1/2. what is the probability of having no girls?

- anonymous

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- anonymous

suppose you have a coin. what is the probability of it landing heads?

- anonymous

ok i know the answer to the question is .0313, anyone know how?

- anonymous

see if 1/32 is 0.0313

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## More answers

- anonymous

yeah how did you get 32

- anonymous

the probability of having a girl is 1/2. so the probability of having a boy is 1/2.
in a family of 5 children, all are boys. i.e, there are no girls. so the parents had five boys consecutively.
so the probability of having 5 boys in a row is 1/2 times 1/2 times 1/2 times 1/2 times 1/2

- anonymous

ok thanks, know how to get this one?
a bag contains 6 cherry, 3 orange, and 2 lemon candies. you reach in and take 3 pieces of candy at random. find the probability you with pick 2 cherry and 1 lemon

- anonymous

yes, but do you want the answer or do you want to learn how to do this?

- anonymous

learn how, i know the answer

- anonymous

okay. so suppose you have 2 candies in the bag. one is lemon and one is grape. what is the probability that you will pick the lemon candy?

- anonymous

1/2

- anonymous

okay good. suppose you have three candies. one lemon one grape and one cherry. what is the probability you pick the lemon ?

- anonymous

1/3

- anonymous

okay good. suppose you have three candies, two lemon and one cherry. what is the probability you pick a lemon candy?

- anonymous

2/3

- anonymous

okay very good.
now you have 6 cherry, 3 lemon and 2 grape candies.
what is the probability that you pick one cherry candy?

- anonymous

6/11

- anonymous

okay very good. now, you have already picked one candy. so there are ten candies left. 5 cherry, 3 lemon and 2 grape.
what is the probability that you pick a cherry candy?

- anonymous

5/10 so 1/2

- anonymous

yes, good. now there are 9 candies left. 4 cherry, 3 lemon and 2 grape. what is the probability that you pick a lemon candy?

- anonymous

3/9, and then you multiply right? thats how i tried to solve the original one but i got the wrong answer

- anonymous

yes, so the probability that you pick 2 cherry candies in a row and then one lemon candy is 6/11 times 1/2 times 1/3.

- anonymous

for 6 cherry, 3 orange, and 2 lemon; the prob of 2 cherry and 1 lemon: answer is supposed to be .1818

- anonymous

solving its that way gets .0909

- anonymous

the question says there are only 2 lemon candies and there are 3 orange candies. so for the third try, you pick a lemon candy out of 9 candies, the probability of that is 2/9
so the answer should be 6/11 times 1/2 times 2/9

- anonymous

yeah i can do that and get .0606; but the book says the answer is supposed to be .1818

- anonymous

thats why im confused

- anonymous

wait, is that supposed to be in that order?

- anonymous

it says at random

- anonymous

yeah it says random, but is the expected answer 1 cherry then 1 cherry then 1 lemon or is it that you pick three candies and you end up with 2 cherries and 1 lemon?

- anonymous

okay looks like you are not reaching in three times. you just reach in once and take three candies.

- anonymous

it says "you reach in and take 3 pieces of candy at random"

- anonymous

do you know how to figure it out that way?

- anonymous

yeah. you have to do it the following way:
6C2/11C3 times 2C1/11C3

- anonymous

c?

- anonymous

have you done permutations and combinations? BTW ignore my answer. that is incorrect. I will calculate the correct answer and post it here.

- anonymous

my teacher gave us problems to do but never taught us how, but yes we are supposed to be doing permutations and combinations. any quick formulas i can jot down for the test?

- anonymous

The answer is 6C2 times 2C1 divided by 11C3

- anonymous

ohh ok that makes sense! thanks!

- anonymous

so that is 15 times 2 divided by 165 = 30/165 = 0.181818181

- anonymous

you dont know how to do combinations?

- anonymous

nope:(

- anonymous

then how did it make sense to you?

- anonymous

she showed us the calculator commands for the c but didnt show us what it was for, now i know

- anonymous

http://www.mathsisfun.com/combinatorics/combinations-permutations.html

- anonymous

read through that and ask me if you have doubts.

- anonymous

thanks soo much!

- anonymous

probability in poker, a flush in any suit?

- anonymous

what is your question?

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