a family has 5 children. the probability of having a girl is 1/2. what is the probability of having no girls?

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this

and **thousands** of other questions.

- anonymous

- jamiebookeater

I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this

and **thousands** of other questions

- anonymous

suppose you have a coin. what is the probability of it landing heads?

- anonymous

ok i know the answer to the question is .0313, anyone know how?

- anonymous

see if 1/32 is 0.0313

Looking for something else?

Not the answer you are looking for? Search for more explanations.

## More answers

- anonymous

yeah how did you get 32

- anonymous

the probability of having a girl is 1/2. so the probability of having a boy is 1/2.
in a family of 5 children, all are boys. i.e, there are no girls. so the parents had five boys consecutively.
so the probability of having 5 boys in a row is 1/2 times 1/2 times 1/2 times 1/2 times 1/2

- anonymous

ok thanks, know how to get this one?
a bag contains 6 cherry, 3 orange, and 2 lemon candies. you reach in and take 3 pieces of candy at random. find the probability you with pick 2 cherry and 1 lemon

- anonymous

yes, but do you want the answer or do you want to learn how to do this?

- anonymous

learn how, i know the answer

- anonymous

okay. so suppose you have 2 candies in the bag. one is lemon and one is grape. what is the probability that you will pick the lemon candy?

- anonymous

1/2

- anonymous

okay good. suppose you have three candies. one lemon one grape and one cherry. what is the probability you pick the lemon ?

- anonymous

1/3

- anonymous

okay good. suppose you have three candies, two lemon and one cherry. what is the probability you pick a lemon candy?

- anonymous

2/3

- anonymous

okay very good.
now you have 6 cherry, 3 lemon and 2 grape candies.
what is the probability that you pick one cherry candy?

- anonymous

6/11

- anonymous

okay very good. now, you have already picked one candy. so there are ten candies left. 5 cherry, 3 lemon and 2 grape.
what is the probability that you pick a cherry candy?

- anonymous

5/10 so 1/2

- anonymous

yes, good. now there are 9 candies left. 4 cherry, 3 lemon and 2 grape. what is the probability that you pick a lemon candy?

- anonymous

3/9, and then you multiply right? thats how i tried to solve the original one but i got the wrong answer

- anonymous

yes, so the probability that you pick 2 cherry candies in a row and then one lemon candy is 6/11 times 1/2 times 1/3.

- anonymous

for 6 cherry, 3 orange, and 2 lemon; the prob of 2 cherry and 1 lemon: answer is supposed to be .1818

- anonymous

solving its that way gets .0909

- anonymous

the question says there are only 2 lemon candies and there are 3 orange candies. so for the third try, you pick a lemon candy out of 9 candies, the probability of that is 2/9
so the answer should be 6/11 times 1/2 times 2/9

- anonymous

yeah i can do that and get .0606; but the book says the answer is supposed to be .1818

- anonymous

thats why im confused

- anonymous

wait, is that supposed to be in that order?

- anonymous

it says at random

- anonymous

yeah it says random, but is the expected answer 1 cherry then 1 cherry then 1 lemon or is it that you pick three candies and you end up with 2 cherries and 1 lemon?

- anonymous

okay looks like you are not reaching in three times. you just reach in once and take three candies.

- anonymous

it says "you reach in and take 3 pieces of candy at random"

- anonymous

do you know how to figure it out that way?

- anonymous

yeah. you have to do it the following way:
6C2/11C3 times 2C1/11C3

- anonymous

c?

- anonymous

have you done permutations and combinations? BTW ignore my answer. that is incorrect. I will calculate the correct answer and post it here.

- anonymous

my teacher gave us problems to do but never taught us how, but yes we are supposed to be doing permutations and combinations. any quick formulas i can jot down for the test?

- anonymous

The answer is 6C2 times 2C1 divided by 11C3

- anonymous

ohh ok that makes sense! thanks!

- anonymous

so that is 15 times 2 divided by 165 = 30/165 = 0.181818181

- anonymous

you dont know how to do combinations?

- anonymous

nope:(

- anonymous

then how did it make sense to you?

- anonymous

she showed us the calculator commands for the c but didnt show us what it was for, now i know

- anonymous

http://www.mathsisfun.com/combinatorics/combinations-permutations.html

- anonymous

read through that and ask me if you have doubts.

- anonymous

thanks soo much!

- anonymous

probability in poker, a flush in any suit?

- anonymous

what is your question?

Looking for something else?

Not the answer you are looking for? Search for more explanations.