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toxicsugar22
 5 years ago
how do u solve
(2x+3x^2)(3+2xx^2+2x^4)
toxicsugar22
 5 years ago
how do u solve (2x+3x^2)(3+2xx^2+2x^4)

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amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0whats your definition of solve?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0to me; solve would be to distribute each term in the left thru the paranethesis and then comcine like terms

toxicsugar22
 5 years ago
Best ResponseYou've already chosen the best response.0sorry Find the first three terms of the product in ascending powers (2x+3x^2)(3+2xx^2+2x^4)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0ascending eh...from little power to biggest...

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.06 +4x 3x+9x^22x^22x^2...if I see it right :) 6 +x +5x^2

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0and I think i see others....hold that

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.03 +2x x^2 * 2 x +3x^2  9x^2+0+0 3x2x^2+0 6+4x2x^2  6 +x +5x^2.....yeah, that should be it

toxicsugar22
 5 years ago
Best ResponseYou've already chosen the best response.0can u help me with one more

toxicsugar22
 5 years ago
Best ResponseYou've already chosen the best response.0and this time let me do it and you do it also and then we can compare ou answers to see if i got it

toxicsugar22
 5 years ago
Best ResponseYou've already chosen the best response.0(12x^2x^4)(4+x^22x^4)

toxicsugar22
 5 years ago
Best ResponseYou've already chosen the best response.0so i got 4+9x^2+5x^6

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0the lowest powers are x^0; x^2 and x^4

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.04  7x^2 8x^4 ...had a typo :) 4x^0 = 4 x^2 8x^2 = 7x^2 2x^4 2x^2 4x^4 = 8x^4
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