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anonymous
 5 years ago
factor 225(x+8)^2
anonymous
 5 years ago
factor 225(x+8)^2

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Do you know the formula of the square difference? \[a^2b^2=(ab)(a+b)\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no i wasnt aware of that one

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Well you should use this formula, you can rewrite your expression as: \[15^2(x+8)^2\] Now you have a=15, and b=x+8. Tell me what you think it would look like after factorization?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You're smart. You just made a little mistake with a sign. Deal with x+8 as a combination at first. So when you subtract, a minus sign will go to both x and 8.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0HMM not sure i understand that one, thank you for the compliment btw

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Well, see here: \[15^2(x+8)^2=(15(x+8))(15+(x+8))=(15x8)(15+x+8)\] \[=(7x)(23+x)\] And yes you really are good!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ohhh i see it now witht the extra parens lol ok, haha and thanks again but your really way smarter man

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0hey i have another one to ask if can help me still?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Yeah sure, just one :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok haha its Cos((pi/2)x)/sin((pi/2)x)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\cos(\pi/2x)\div \sin(\pi/2x)\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i know i have to use the sum and difference id's for sin and cos but im hitting a wall

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You want to simplify: \[{\cos({\pi \over 2}x) \over \sin({\pi \over 2}x)}?\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yea the question says find

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0It says find? A bit strange. Anyway, it clearly wants you to apply the following two formulas: \[\cos ({\pi \over 2}x)=\sin x ..(1)\] \[\sin({\pi \over 2}x)=\cos x .. (2)\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i think, would it come out to tangent?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Exactly!! Didn't I just I say you're smart?!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So, applying the two formulas gives: \[{\sin x \over \cos x}=\tan x\] I don't know if it's giving any values for x.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no it was just asking for an equal trig function, i didnt know those equations though, putting them in my notes, thanks man, youve helped me alot!!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You're welcome. I am sure you're very good at math, and you pick things quickly. Good luck!!
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