toxicsugar22
  • toxicsugar22
Find the indicated term in each poduct (4+2x-x^2)(2-3x+2x^2) for x^2
Physics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
toxicsugar22
  • toxicsugar22
someone help
anonymous
  • anonymous
im unsure of what its asking for, the wording is weird, does it want the co-efficient of the x^2 term?
toxicsugar22
  • toxicsugar22
yes

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
ok, if you multiply out the brackets and simplify you get: 8-8x- 4x^2 + 7x^3 -2x^4 so for the x^2 it's 4. Is this what you're looking for?
toxicsugar22
  • toxicsugar22
yes
toxicsugar22
  • toxicsugar22
can u also help me with one more
toxicsugar22
  • toxicsugar22
question
toxicsugar22
  • toxicsugar22
Find the first three terms of the product in acending powers. (1-2x^2-x^4)(4+x^2-2x^4)
anonymous
  • anonymous
you get \[4 + 9x^{2} - 6x ^{4} + 3x ^{6} + 2x ^{8} \] which will give you co-efficients of 4, 0 and -9 if you include \[x ^{0}\] as a term
toxicsugar22
  • toxicsugar22
thats the answer
toxicsugar22
  • toxicsugar22
is thaat the answer
anonymous
  • anonymous
yeh

Looking for something else?

Not the answer you are looking for? Search for more explanations.