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do you know the quadratic formula?
no..i don think so?
ok we can try to factor it then
yeah thats what im doing..i have to factor it
a=4, b=8, c=-21 Find factors of a*c that add up to be b
what is a*c?
right! a*c=-4(21) play with this until you get the sum of the factors to be b=8 -4+21 is not 8 a*c=12(-7) 12-7 is not 8 a*c=6(-14) is 6-14 =8?
but we want 8 how can we get 8
what if you said a*c=-6(14) what is the sum of those two factors?
now replace the bx term with what you just found but you need an x behind each term so it equals bx
ohhh okay then you have to group it right?
so then it would be(4x^2+14x)(-6x-21)=0 which then what?
what do 4x^2 and 14x have in common?____________ what do -6x and -21 have in common?___________
4x ? idk
2x -3 so the first 2 terms we factor out 2x(2x+7) so the second 2 terms we factor out -3(2x+7) so 4x^2+14x-6x-21=2x(2x+7)-3(2x+7) can we do anything else?
you still there?
we are almost there
yeha ohh aha i would have never thought of that..
then you do 2x-3=0 and 2x+7=0..
there is 2x+7 in both of those two terms above so we can factor a 2x+7 out of both giving us (2x+7)(2x-3) this expression was orignally set =0 so we have (2x+7)(2x-3)=0 so either 2x+7=0 or 2x-3=0 when i say both its the exclusive kind
you got that part? was the factoring the problem you were having?
then the answer is x=2/3 and x=2/7!!
omg thanks soo much for your help!! haha sorry that took me forever to figure out:/ thanks though!
x=2/3 is right but x=-7/2 for the second one