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anonymous

  • 5 years ago

solve for x: logx+log(x+21)=2

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  1. anonymous
    • 5 years ago
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    the answer is 4 I just don't know how to get there

  2. myininaya
    • 5 years ago
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    log(y)+log(z)=log(yz) tried to used that here

  3. myininaya
    • 5 years ago
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    log[x(x+21)]=2

  4. sasogeek
    • 5 years ago
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    alexa have you made an attempt to solve the question?

  5. anonymous
    • 5 years ago
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    yes i have and I come up with something completely different. im not sure whether to use the quotient, product, or power rule

  6. sasogeek
    • 5 years ago
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    combine the product and quotient rule

  7. myininaya
    • 5 years ago
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    to get rid of the log write base 10 on both sides so we have x(x+21)=10^2

  8. sasogeek
    • 5 years ago
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    log(x(x+21)=2 logx^2+21x=2 =>10^2=x^2+21

  9. sasogeek
    • 5 years ago
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    ummmm 21x

  10. myininaya
    • 5 years ago
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    100=x^2+21x

  11. myininaya
    • 5 years ago
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    right

  12. sasogeek
    • 5 years ago
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    simple quadratics

  13. sasogeek
    • 5 years ago
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    alexa I hope its alright now... problem solved?

  14. anonymous
    • 5 years ago
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    I can go from here, thanks

  15. sasogeek
    • 5 years ago
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    you're welcome :)

  16. sasogeek
    • 5 years ago
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    heyy btw alexa, you got msn or fb or some personal contact we can talk later, I'd appreciate it :/

  17. myininaya
    • 5 years ago
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    hey alex make sure you check your answers because we can't have log(negative)

  18. anonymous
    • 5 years ago
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    sorry but I dont like to give my personal information out unless I personally know the individual, no offense. and thanks, I will.

  19. sasogeek
    • 5 years ago
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    np, understood :)

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