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You can use x= R cos t and y = R sin t
r = 9sqrt(2)
and its some form of 45 degree angle
Find R by: R= sqrt(x^2 + y ^2)
angle = 135
I know how to use the formula, but I can't use decimals as the answer.
I have to put the answer in an x and y format.
(9sqrt(2), 135) or the radian (3pi/4)
how do u get this answer?
been going over spherical and cylindrical coordinates today lol
well; i notice that both ax and y are the same; the only angle with that is a 45 degree; the hyp of a 45 degree is sqrt(2)
r = 9 times bigger than sqrt(2) = 9sqrt(2)
What about this one? (-√21, -√7)
and the x=- and y=+ tells me its in the Q2
r = sqrt(28) the x=- and y=- is in the Q3
tan^1(sqrt(7)/sqrt(21)) is the angle
sqrt(21+7) = sqrt(28) right?
yeah, where to u get the 7 from?
or why use the 7
sqrt(7)^2 = 7
7*4 = 28 so...2sqrt(7) = r
tan^-1(sqrt(7)/sqrt(21)) + pi is the angle
we got 30 +pi :)
so the y would be 7pi/6
the angle = 7pi/6
would it be (sqrt1,0)
thats facing left.... r = 1; theta = pi
why does theta = 0
i mean pi
it 1 from the origin; so r=1 and its 180 or pi from the pos x axis
theta doesnt equal 0, the y coord = 0
the angle = pi
if we turn by pi and move out by 1 we come to -1,0
yes :) 1,pi
ok, a little change in direction.
Convert the equation to polar form. 5x=5y
thats the same as y = x which is r = t cos(pi/4)
or rather: (r,pi/4) i think
could be +-r, pi/4
whats our options for answers?
pi/4 is wrong, i tried thaat
y=x is a 45 degree line.... cant be another angle :)
x = r cos(pi/4) y = r sin(pi/4)
i'm so confused right now :(
maybe 5r, but thats rather redundant
5x = 5y right? 5r cos(pi/4) = 5r sin(pi/4)
the 5rs can be removed and you get; cos(pi/4)=sin(pi/4)
is it 5r/sqrt2
dont know; what formats you got to choose from?
i have no idea. what formats are there?
if its multiple choice; then they give you options to choose from....any options to narrow this down with?
no, no multiple choice.
here's another example: x^2+y^2=16
r^2 = 16
that would be 4. I tried that but it says it's wrong.
then i got no idea what your program wants as an answer :)
i got it i had to put it in as r=4
would it be sqrt2
y=2 r sin(t) = 2
r = 2/sin(t) ?
I don't get it.
the question is Convert the equation to polar form. y=2