- anonymous

Convert the rectangular coordinates to polar coordinates with r > 0 and 0 < θ < 2π.
(-9, 9)

- chestercat

I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this

and **thousands** of other questions

- anonymous

You can use x= R cos t and y = R sin t

- amistre64

r = 9sqrt(2)

- amistre64

and its some form of 45 degree angle

Looking for something else?

Not the answer you are looking for? Search for more explanations.

## More answers

- amistre64

q2

- anonymous

Find R by: R= sqrt(x^2 + y ^2)

- amistre64

angle = 135

- anonymous

I know how to use the formula, but I can't use decimals as the answer.

- anonymous

I have to put the answer in an x and y format.

- amistre64

(9sqrt(2), 135) or the radian (3pi/4)

- anonymous

how do u get this answer?

- amistre64

been going over spherical and cylindrical coordinates today lol

- amistre64

well; i notice that both ax and y are the same; the only angle with that is a 45 degree; the hyp of a 45 degree is sqrt(2)

- amistre64

r = 9 times bigger than sqrt(2) = 9sqrt(2)

- anonymous

What about this one?
(-√21, -√7)

- anonymous

oh ok

- amistre64

and the x=- and y=+ tells me its in the Q2

- amistre64

r = sqrt(28)
the x=- and y=- is in the Q3

- anonymous

sqrt28?

- amistre64

tan^1(sqrt(7)/sqrt(21)) is the angle

- amistre64

sqrt(21+7) = sqrt(28) right?

- anonymous

yeah, where to u get the 7 from?

- anonymous

or why use the 7

- amistre64

sqrt(7)^2 = 7

- amistre64

7*4 = 28 so...2sqrt(7) = r

- amistre64

tan^-1(sqrt(7)/sqrt(21)) + pi is the angle

- amistre64

we got 30 +pi :)

- anonymous

so the y would be 7pi/6

- amistre64

yes :)

- amistre64

the angle = 7pi/6

- anonymous

(-1, 0)

- anonymous

would it be (sqrt1,0)

- amistre64

thats facing left....
r = 1; theta = pi

- anonymous

why does theta = 0

- anonymous

i mean pi

- amistre64

it 1 from the origin; so r=1
and its 180 or pi from the pos x axis

- amistre64

theta doesnt equal 0, the y coord = 0

- anonymous

the angle = pi

- amistre64

if we turn by pi and move out by 1 we come to -1,0

- anonymous

it's (1,pi)

- amistre64

yes :) 1,pi

- anonymous

ok, a little change in direction.

- anonymous

Convert the equation to polar form.
5x=5y

- amistre64

thats the same as y = x which is
r = t cos(pi/4)

- amistre64

or rather: (r,pi/4) i think

- amistre64

could be +-r, pi/4

- amistre64

whats our options for answers?

- anonymous

pi/4 is wrong, i tried thaat

- amistre64

y=x is a 45 degree line.... cant be another angle :)

- amistre64

x = r cos(pi/4)
y = r sin(pi/4)

- anonymous

i'm so confused right now :(

- amistre64

maybe 5r, but thats rather redundant

- amistre64

5x = 5y right?
5r cos(pi/4) = 5r sin(pi/4)

- amistre64

the 5rs can be removed and you get; cos(pi/4)=sin(pi/4)

- anonymous

is it 5r/sqrt2

- amistre64

dont know; what formats you got to choose from?

- anonymous

i have no idea. what formats are there?

- amistre64

if its multiple choice; then they give you options to choose from....any options to narrow this down with?

- anonymous

no, no multiple choice.

- anonymous

here's another example: x^2+y^2=16

- amistre64

r^2 = 16

- anonymous

that would be 4. I tried that but it says it's wrong.

- amistre64

then i got no idea what your program wants as an answer :)

- anonymous

i got it i had to put it in as r=4

- anonymous

y=2

- amistre64

:)

- anonymous

would it be sqrt2

- amistre64

y=2
r sin(t) = 2

- amistre64

r = 2/sin(t) ?

- anonymous

I don't get it.

- anonymous

the question is Convert the equation to polar form.
y=2

Looking for something else?

Not the answer you are looking for? Search for more explanations.