anonymous
  • anonymous
Convert the rectangular coordinates to polar coordinates with r > 0 and 0 < θ < 2π. (-9, 9)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
You can use x= R cos t and y = R sin t
amistre64
  • amistre64
r = 9sqrt(2)
amistre64
  • amistre64
and its some form of 45 degree angle

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More answers

amistre64
  • amistre64
q2
anonymous
  • anonymous
Find R by: R= sqrt(x^2 + y ^2)
amistre64
  • amistre64
angle = 135
anonymous
  • anonymous
I know how to use the formula, but I can't use decimals as the answer.
anonymous
  • anonymous
I have to put the answer in an x and y format.
amistre64
  • amistre64
(9sqrt(2), 135) or the radian (3pi/4)
anonymous
  • anonymous
how do u get this answer?
amistre64
  • amistre64
been going over spherical and cylindrical coordinates today lol
amistre64
  • amistre64
well; i notice that both ax and y are the same; the only angle with that is a 45 degree; the hyp of a 45 degree is sqrt(2)
amistre64
  • amistre64
r = 9 times bigger than sqrt(2) = 9sqrt(2)
anonymous
  • anonymous
What about this one? (-√21, -√7)
anonymous
  • anonymous
oh ok
amistre64
  • amistre64
and the x=- and y=+ tells me its in the Q2
amistre64
  • amistre64
r = sqrt(28) the x=- and y=- is in the Q3
anonymous
  • anonymous
sqrt28?
amistre64
  • amistre64
tan^1(sqrt(7)/sqrt(21)) is the angle
amistre64
  • amistre64
sqrt(21+7) = sqrt(28) right?
anonymous
  • anonymous
yeah, where to u get the 7 from?
anonymous
  • anonymous
or why use the 7
amistre64
  • amistre64
sqrt(7)^2 = 7
amistre64
  • amistre64
7*4 = 28 so...2sqrt(7) = r
amistre64
  • amistre64
tan^-1(sqrt(7)/sqrt(21)) + pi is the angle
amistre64
  • amistre64
we got 30 +pi :)
anonymous
  • anonymous
so the y would be 7pi/6
amistre64
  • amistre64
yes :)
amistre64
  • amistre64
the angle = 7pi/6
anonymous
  • anonymous
(-1, 0)
anonymous
  • anonymous
would it be (sqrt1,0)
amistre64
  • amistre64
thats facing left.... r = 1; theta = pi
anonymous
  • anonymous
why does theta = 0
anonymous
  • anonymous
i mean pi
amistre64
  • amistre64
it 1 from the origin; so r=1 and its 180 or pi from the pos x axis
amistre64
  • amistre64
theta doesnt equal 0, the y coord = 0
anonymous
  • anonymous
the angle = pi
amistre64
  • amistre64
if we turn by pi and move out by 1 we come to -1,0
anonymous
  • anonymous
it's (1,pi)
amistre64
  • amistre64
yes :) 1,pi
anonymous
  • anonymous
ok, a little change in direction.
anonymous
  • anonymous
Convert the equation to polar form. 5x=5y
amistre64
  • amistre64
thats the same as y = x which is r = t cos(pi/4)
amistre64
  • amistre64
or rather: (r,pi/4) i think
amistre64
  • amistre64
could be +-r, pi/4
amistre64
  • amistre64
whats our options for answers?
anonymous
  • anonymous
pi/4 is wrong, i tried thaat
amistre64
  • amistre64
y=x is a 45 degree line.... cant be another angle :)
amistre64
  • amistre64
x = r cos(pi/4) y = r sin(pi/4)
anonymous
  • anonymous
i'm so confused right now :(
amistre64
  • amistre64
maybe 5r, but thats rather redundant
amistre64
  • amistre64
5x = 5y right? 5r cos(pi/4) = 5r sin(pi/4)
amistre64
  • amistre64
the 5rs can be removed and you get; cos(pi/4)=sin(pi/4)
anonymous
  • anonymous
is it 5r/sqrt2
amistre64
  • amistre64
dont know; what formats you got to choose from?
anonymous
  • anonymous
i have no idea. what formats are there?
amistre64
  • amistre64
if its multiple choice; then they give you options to choose from....any options to narrow this down with?
anonymous
  • anonymous
no, no multiple choice.
anonymous
  • anonymous
here's another example: x^2+y^2=16
amistre64
  • amistre64
r^2 = 16
anonymous
  • anonymous
that would be 4. I tried that but it says it's wrong.
amistre64
  • amistre64
then i got no idea what your program wants as an answer :)
anonymous
  • anonymous
i got it i had to put it in as r=4
anonymous
  • anonymous
y=2
amistre64
  • amistre64
:)
anonymous
  • anonymous
would it be sqrt2
amistre64
  • amistre64
y=2 r sin(t) = 2
amistre64
  • amistre64
r = 2/sin(t) ?
anonymous
  • anonymous
I don't get it.
anonymous
  • anonymous
the question is Convert the equation to polar form. y=2

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