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linda

  • 5 years ago

Hey can you help with this one: express in simplest form: 3/ the square root of 3a^2b. In other words, 3 is the numerator and the denominator is the square root of 3a^2b

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  1. anonymous
    • 5 years ago
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    \[\sqrt{3}*a ^{-b}\]

  2. Linda
    • 5 years ago
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    can you tell me what you did to get there?

  3. Linda
    • 5 years ago
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    I can't figure out how to get there. I thought maybe to multiply top and bottom of fraction by square root of 3a^2b. Does that sound right?

  4. anonymous
    • 5 years ago
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    yeah that sounds correct to me

  5. Linda
    • 5 years ago
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    so then I end up with 3*sq rt of 3a^2b on the top and 3a^2b in the denominator. but then what do I do next??

  6. anonymous
    • 5 years ago
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    the 3s will cancel and your left with sqrt of 3a^2b / a^2 b

  7. Linda
    • 5 years ago
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    OK i've got you so far. thanks. But then what?

  8. Linda
    • 5 years ago
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    I don't know what to do with numbers when they are in the square root.

  9. anonymous
    • 5 years ago
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    it cant be simplified anymore

  10. Linda
    • 5 years ago
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    oh really? someone else gave me the answer sq rt 3 * a^-b not sure how they got it. It was inik

  11. anonymous
    • 5 years ago
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    you cant just cancel out the denominator like that because because the numerator is under a sq rt

  12. Linda
    • 5 years ago
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    ok so the numerator must stay as is? And so the problem cannot be simplified any further?

  13. anonymous
    • 5 years ago
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    thats what i think.

  14. Linda
    • 5 years ago
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    OK thanks!

  15. anonymous
    • 5 years ago
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    glad i could help

  16. Linda
    • 5 years ago
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    this math stuff can make a person crazy

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