Find the vertex, focus, and directrix of the parabola. (y+2)^2 = -2(x-6) I found the vertex which is (6,-2) AND 4p=-2 p=-2/4 p=-1/2

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Find the vertex, focus, and directrix of the parabola. (y+2)^2 = -2(x-6) I found the vertex which is (6,-2) AND 4p=-2 p=-2/4 p=-1/2

Mathematics
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v = (6,-2) is right 4a = -2 a = |-1/2| = 1/2
it opens to the right so the focus is (6,-1.5)
and the D: x = -2.5

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Other answers:

thats backwards lol
it opens to the left; becasue of the -2.... switch the focus and directix i gave yuo
oh.. ok
the focus is wrong. says the program
focus should be...doh!!, modify the x not the y grrr!!
V = (6,-2) F=(5.5,-2) D= x=6.5

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