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anonymous
 5 years ago
Find the volume of the solid obtained by rotating the region R bounded by the curves , y =1/(1+x^2), y= 0, x = 0 and x=3 about the xaxis.
anonymous
 5 years ago
Find the volume of the solid obtained by rotating the region R bounded by the curves , y =1/(1+x^2), y= 0, x = 0 and x=3 about the xaxis.

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amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1sec(t)^2 is what that amounts to ... right?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1regardless; its the volume of: pi [S] [1/(1+x^2)]^2 dx ; [0,3]

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1x = tan dx = sec^2 dt sec^2 dt .....really? t? lol sec^2

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1nah... sec^2 dt  = cos^2 dt thats it sec^4

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1cos^2 = 1/2 + cos(2t)/2 t/2 + sin(2t)/4 is our integration

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1t = tan^1(x) so... tan^1(x)/2 + cos(2(tan^1(x)))/2

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.135.78 0.4 = 31.78....or so

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1that wa typoed lol...ack!!

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1tan^1(x)/2 + sin(2(tan^1(x))/4

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1we might be easier to just convert the interval to match the "t" tan(t) = x when x = 0 t=0 when x=3 t= 71.56 so; 0/2 + sin(2(0))/4 = 0 71.56/2 + sin(2(71.56))/4 = 35.78 + 0.15 = 35.93....hopefully :)
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