anonymous
  • anonymous
I really need help with this..I need to rewrite this to a single logarithm with coefficient one 1/2logx-1/3logy-2logz
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
log sq.rt x-1 / log y / log z^2
anonymous
  • anonymous
I didnt think you could write all 3 in a divison, i got to : log x^1/2-logy^1/3-logz^2 and now im stuck
anonymous
  • anonymous
i know the minus goes to division but i dont believe you can do all three dividing eachother

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
then multiply by reciprocal or sth?
anonymous
  • anonymous
1/2logx-1/3logy-2logz =log [x^(1/2)] - log [y^(1/3)] - log [z^2] =log [ sqrt(x) / (cbrt(y) z^2) ]
anonymous
  • anonymous
what is cbrt?
anonymous
  • anonymous
cube root
anonymous
  • anonymous
cubic root
anonymous
  • anonymous
cube root :P
anonymous
  • anonymous
ok great thankyou both!
anonymous
  • anonymous
my pleasure :)

Looking for something else?

Not the answer you are looking for? Search for more explanations.