I really need help with this..I need to rewrite this to a single logarithm with coefficient one 1/2logx-1/3logy-2logz

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I really need help with this..I need to rewrite this to a single logarithm with coefficient one 1/2logx-1/3logy-2logz

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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log sq.rt x-1 / log y / log z^2
I didnt think you could write all 3 in a divison, i got to : log x^1/2-logy^1/3-logz^2 and now im stuck
i know the minus goes to division but i dont believe you can do all three dividing eachother

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Other answers:

then multiply by reciprocal or sth?
1/2logx-1/3logy-2logz =log [x^(1/2)] - log [y^(1/3)] - log [z^2] =log [ sqrt(x) / (cbrt(y) z^2) ]
what is cbrt?
cube root
cubic root
cube root :P
ok great thankyou both!
my pleasure :)

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