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help

  • 5 years ago

REALLY NEED HELP PLEASE!!!! PROBLEM: If cos(t) = -3/5 where pi<t<3pi/2, find the values of the following trigonometric functions: cos(2t) = sin(2t) = cos(t/2) = sin(t/2) = NOTE: Give exact answers, do not use decimal numbers. The answer should be a fraction or an arithmetic expression. If the answer involves a square root it should be entered as sqrt; e.g. the square root of 2 should be written sqrt(2).

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  1. anonymous
    • 5 years ago
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    based on given info, we'll get sin t= -4/5, tan t= 4/3. cos (2t) = 2 cos^2 (t) -1 sin(2t)= 2 sin t cos t just you half angle formulae to solve cos (t/2) and sin (t/2)

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  2. help
    • 5 years ago
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    Nope, wrong. Thanks anyways

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