Is the limit of ln x as x approaches to infiniti 1?

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Is the limit of ln x as x approaches to infiniti 1?

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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\[\lim_{x \rightarrow \infty} \ln x / x = (1/x)/1 = 1/x\] \[1/\infty = 0\] I used L'Hopital's rule
Oh I just meant ln x not lnx/x. Thanks though
oh if u went ln x then it is unbounded and will be infinity

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Attached is a plot of Log[x], "Ln[x]", from x = 0 through x=10^100
a plot of 0 to 10^100 does not always demonstrate end behavior, inthis case it does....but not always
Just offered as a "it seems to be the case...".

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