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anonymous

  • 5 years ago

okay one more confusion. how does 3^(n+1) divided by 3^(n+2) simplify to just plain old 3???

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  1. anonymous
    • 5 years ago
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    it doesn't it simplifies to 1/3

  2. anonymous
    • 5 years ago
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    oh. so I guess I had it wrong. how would I go about simplifying the expression?

  3. anonymous
    • 5 years ago
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    \[3^{n+1}/3^{n+2} = 3^n \times 3^1 \div s^n 3^2 = 1/3\]

  4. anonymous
    • 5 years ago
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    remember ur rules of adding and subtracting exponents

  5. anonymous
    • 5 years ago
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    3^(n+2) = 3^(n+1+1) = 3^(n+1) * 3 so that why 3^(n+1) divided by 3^(n+2) = 3^(n+1) / 3^(n+1) * 3 =1/3

  6. anonymous
    • 5 years ago
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    so it equals 1/3. NOT just 3?

  7. anonymous
    • 5 years ago
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    yes it equals 1/3

  8. anonymous
    • 5 years ago
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    yep. i guess that's how it works.

  9. anonymous
    • 5 years ago
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    okay I am going to look over it and try to understand it. thank you both for the thorough explanations! :) much appreciated.

  10. anonymous
    • 5 years ago
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    welcome ;)

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