okay one more confusion. how does 3^(n+1) divided by 3^(n+2) simplify to just plain old 3???

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okay one more confusion. how does 3^(n+1) divided by 3^(n+2) simplify to just plain old 3???

Mathematics
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it doesn't it simplifies to 1/3
oh. so I guess I had it wrong. how would I go about simplifying the expression?
\[3^{n+1}/3^{n+2} = 3^n \times 3^1 \div s^n 3^2 = 1/3\]

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Other answers:

remember ur rules of adding and subtracting exponents
3^(n+2) = 3^(n+1+1) = 3^(n+1) * 3 so that why 3^(n+1) divided by 3^(n+2) = 3^(n+1) / 3^(n+1) * 3 =1/3
so it equals 1/3. NOT just 3?
yes it equals 1/3
yep. i guess that's how it works.
okay I am going to look over it and try to understand it. thank you both for the thorough explanations! :) much appreciated.
welcome ;)

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