At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions.

I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions

ask

\[\lim_{n \rightarrow \infty} ((n!)^{1/n})/n\]

fun!

omg

Pretty sure the factorial will dominate, but let's find out =)

givng up

how do i go about it polpak?

Well, on top you have \(\infty^0\)

Which by itself is an indeterminate form

agreed

The limit does exist and is finite.

yes apples thats correct

is anyone working on it?

I'd suggest using the Squeeze Theorem.

what is that? would you explain?

Yes.

ok i understand now.
but how is a the lower limit and the upper limit of a function found?

I think it's easy to find the limit using the definition, that apples just mentioned above, for e.

that was a good explanation apples. thank you.

yea i got it anwar..=)

You already found the answer.. Never mind then :)

No prob