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anonymous
 5 years ago
some one plz help me
need help solve the system of equations by graphing then classify the system as consistent or inconsistent, and as dependent or independent 4xy=15 x+5y=12 step by step plz
anonymous
 5 years ago
some one plz help me need help solve the system of equations by graphing then classify the system as consistent or inconsistent, and as dependent or independent 4xy=15 x+5y=12 step by step plz

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0These are linear equations in two variables If they have a common solution, then they will cross each other at a point and hence will be consistent. We put them in the form ax + by + c = 0 4x  y  15 = 0 and x + 5y + 12 = 0 Now If a1/a2≠b1/b2 then they will intersect at one point and will have a unique and consistent solution Here a1/a2 = 4/1 and b1/b2 = 1/5 Since a1/a2 is not equal to b1/b2, therefore it will have a unique solution and they are consistent.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Also since they share only one common point, they are consistent and independent

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0For your info, if \[a1/a2 \neq b1/b2\] then they are consistent and independent as they will cut each other at one point if \[a1/a2 = b1/b2 = c1/c2\] then they r consistent a dependent as the two lines will lie on each other if \[a1/a2 = b1/b2 \neq c1/c2\] then they r independent as they r parallel lines and will not meet/cut each other at even one point Hope this clears everything....

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0because i have no idea how to do this

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the other guy is telling me one thing and someone else told me another

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0First you have to put the given equations in ax + by + c = 0 form See how I did it.... Is that clear or not??

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0No it will be  15 becoz when you shift a term from one side to the other, its sign changes

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So, it will be 4x y  15 = 0

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok and x+5y12=0 for the second equation?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0No, x + 5y + 12 = 0 as sign on  12 will become + when it is shifted to the other side.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Now we check what is the ratio of the coefficients of x in the two equations. Here a1/a2 = 4/1 as in first eqn it is 4x and in the second eqn it is 1

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Then we check for the ratio of the coefficients of the y in the two equations Here b1/b2 = 1/5 as in first eqn it is y and in second eqn it is 5y

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Finally we check for the ratio of the constant terms in the two equations here c1/c2 = 15/12

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0nope lost me when you started talking about ratio's 5y

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0U u/sttod a1/a2 = 4/1 ??

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I guess it wud be easier if cud talk, do u hv a SKYPE account???

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I hv a SKYPE id hakki.singh

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0well it wud hv been very easy if we cud talk.....

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i dont remember any of this from the hmwk

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Maybe u are being taught a different method, mine is very simple and easy to follow if u get the hang once

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0No, first u hv to look at the coefficients of the x terms of both equns In the first one 4 is the coefficient of the term 4x In the second one 1 is the coefficient of the term x

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So, a1/a2 ie the ratio of the coefficients of the x terms of the first eqn and the second eqn is 4/1

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Now we go the y terms

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0In the first eqn it is y and in the second eqn it is 5y so b1 is 1 abd b2 is 5 so b1/b2 is 1/5

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Finally we look at the constant terms Here it is 15 in the first eqn and 12 in the second eqn So, c1/c2 is 15/12

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Now we have to understand the terms consistent/inconsistent and dependent/independent

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0consistent means that the two eqns share at least one or more solutions This means that if their graphs cut each other at one point or the two lines coincide in which case they share infinite solutions inconsistent means that they do not share even one solution i.e. the line never meet

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0And in case they r consistent i.e they share one or more solutions, then they will be independent if they share just one solution and dependent if they share many solutions ie.e the line coincide

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So we can have consistent and dependent consistent and independent and inconsistent

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0it is only one answer and the solution of the system typed in an ordered pair,

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I'm coming to the solution, but is the above classifications as consistent and dependent, consistent and independent and inconsistent clear??

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Fianlly, if a1/a2≠b1/b2 then they are consistent and independent as they will cut each other at one point if a1/a2=b1/b2=c1/c2 then they r consistent a dependent as the two lines will lie on each other if a1/a2=b1/b2≠c1/c2 then they r inconsistent as they r parallel lines and will not meet/cut each other at even one point

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0In your case a1/a2 = 4/1 and b1/b2 = 1/5 So, a1/a2 is not equal to b1/b2, so your pair of equations is consistent and independent

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So, it is now clear tht yr system of pair of eqns is consistent and independent. To draw their graphs, you modify the first equation by separating x and y as follows 4x  15 = y Now put various values like 1 , 0, 1, 4 for x and getting corresponding values of y Understood??

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Similarly modify the second eqn as follows: 5y = x 12 (remember signs change when you shift their side) so, x 12 y =  5 Now, put various values for x and calculate corresponding values of y. Now plot the graphs for the two eqns separately and you will find them cutting each other at one point.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Your intersection point shud b (3, 3)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Hope now everything is clear??

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok and it is consistent and independent

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok ty so much for all your help I really appreciate it

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0U r welcome. In this we have to be clear what consistent/inconsistent and dependent/independent mean. Then using the three ratio checks we can find whether there will be one solution, many solutions or no solution. Do I get a medal for this??
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