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anonymous
 5 years ago
\[\int\limits_{}^{}(\cos x \cos 2x) dx/1cosx\]
anonymous
 5 years ago
\[\int\limits_{}^{}(\cos x \cos 2x) dx/1cosx\]

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[=\int\limits_{}^{}((\cos x1)+(1\cos 2x))dx/(1\cos x)\] \[=\int\limits_{}^{}dx+\int\limits_{}^{}2\sin ^{2}xdx/(1\cos x)\] \[x+\int\limits_{}^{}2\sin ^{2}xdx/(2\sin ^{2}x/2)\] \[x+\int\limits_{}^{}4\cos ^{2}x/2dx\]i think now you can do the simple integration

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0it should be x and how did you get this?? \[\int\limits\limits_{}^{}4\cos ^{2}x/2dx\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes it should be x. sin x=2sin(x/2)cos(x/2). use this in the gration.
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