got a long one f(x) = x+5 and g(x) = x+8 find the following (f+g)(x) then (f-g)(x) and then (fg)(x) last one f/g)(x)

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got a long one f(x) = x+5 and g(x) = x+8 find the following (f+g)(x) then (f-g)(x) and then (fg)(x) last one f/g)(x)

Mathematics
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(f+g)(x)=f(x)+g(x) similar for (f-g)(x) (fg)(x)=f(x)g(x) (f/g)(x)=f(x)/g(x)
? thats not the answers?
u r to substitute the values only

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Other answers:

do u know how to do it?
no? Im stuck I keep getting different answers
ok (f+g)(x)=f(x)+g(x)=x+5+x+8=2x+13
got it?
ah ok
can u do the rest?
I can do the next step,,, how would I do the (fg)(x) one?
(fg)(x)=f(x)g(x)=(x+5)(x+8)=x^2+13x+40
the (f-g) would be 2x-3 for the answer right?
it would be -3 only, x is cancelled out
oh..crap k
did u get the product ?
last one would be x+5/x+8
right
sweet ... think I get it now thank you :)
:)

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