A rectangular pen for a pet is 3ft longer that it is wide, give possible values for the width W of the pen if its area must be between 180 and 460 sqaure feet, inclusivley.

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A rectangular pen for a pet is 3ft longer that it is wide, give possible values for the width W of the pen if its area must be between 180 and 460 sqaure feet, inclusivley.

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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If area is 180 W * ( W + 3) = 180 w^2 + 3w = 180 w = 12 if area is 460, W^2 + 3w = 460, w = 20 12
so that would mean 12ft and 20 ft
No, the width can lie ANYWHERE between 12ft and 20ft. He tested the extreme cases here, and reasoned that a value of W somewhere between 12ft and 20ft would result in an area greater than 180 but less than 460. If you'd like to confirm this fact, try graphing\[Area=w*(w+3)=w^2+3w\] Look at what values of w output values that are between 180 and 460 and you should see that 12ft and 20ft indeed bound these values! I hope that helps solidify your understanding!

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