anonymous
  • anonymous
the sum of the digits of two-digit number is 15. if the digist are reversed the new number is 27 less than the original number. Find the original number
Mathematics
katieb
  • katieb
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yuki
  • yuki
interesting problem
yuki
  • yuki
let's say that the 10th digit is a and the units to be b
yuki
  • yuki
then a + b = 15

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yuki
  • yuki
our two digit number can be represented as 10a + b
yuki
  • yuki
so if you reverse the order it becomes 10b + a
yuki
  • yuki
the new one is 27 less than the original number, so your other equation will be 10b+a = 10a+b -27
yuki
  • yuki
now that you have two equations with two unknowns, you can solve for the system of equations.
anonymous
  • anonymous
please help me with the answer :(
anonymous
  • anonymous
the two eqs are a+b=10 10b+a-10a-b=-27 9a-9b=-27
radar
  • radar
which is it a+b=15 or a+b=10?
anonymous
  • anonymous
ah...a+b=15
anonymous
  • anonymous
Did you guys find the number?
anonymous
  • anonymous
a+b=15 9a-9b=-27 are the two eqs solving the two eqs... a=6 n b=9
radar
  • radar
96 , 9+6=15 69=96-27
anonymous
  • anonymous
So, the original number is 96.
radar
  • radar
Looks like a good Bingo lol
anonymous
  • anonymous
but as yuki took the places of digits,,10a+b gives 69:S
anonymous
  • anonymous
i guess second eq should be 10b+a+27=10a+b ???
radar
  • radar
I gave yuki a medal anyway
radar
  • radar
You're getting one too
anonymous
  • anonymous
:)
anonymous
  • anonymous
n u know i made mistake in solving a qs too :P
radar
  • radar
It is the spirit of the effort that counts.
anonymous
  • anonymous
right...but it surly confuses the one who posts the question
anonymous
  • anonymous
thank you guys u are life saaaavvveeeerrrssss

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