anonymous
  • anonymous
in the problem y= 2/3x+3 2/3 is my slope right if that is so 3 is my first cordinate point to start graphing from
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
to define the line you need only 2 points. if you let x=0, so y=3 2/3 (not 3)... if you let x=3, y = 2/3 *3 +3 2/3 = 2+ 3 2/3
anonymous
  • anonymous
ok that clears up my confusion ty i should be able to graph it now
anonymous
  • anonymous
Terry...should the original equation be\[y=2/3x+3\] or \[y=2/3x + 3(and)2/3\]? That is, I read your initial question to say that you wanted to check that the slope of the equation \[y=2/3x+3\] is 2/3.

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
the problem uis set up in fraction form so its 2/3x +3
anonymous
  • anonymous
Your original question was misleading, I believe, and inik's answer was to a different problem. The slope of the line given by the equation y=2/3x+3 is 2/3, as I believe you indicated. Equations of the form y=mx+b have slope m and y intercept b, so your first point to start graphing from would be the y intercept, b, 3, as you had in your first post. At x=0, y=2/3*0+3 such that the point at x=0 is (0,3).
anonymous
  • anonymous
ok ill try graphing the problem that way and see if that looks better than the previous way i graphed the equation
anonymous
  • anonymous
i get mislead when it comes to graphing equations that include fractions a common mistake alot of people make
anonymous
  • anonymous
It was just the phrasing. Your problem read like this: "in the problem y= 2/3x+3 2/3 is my slope right" It would have been more clear had you said "in the problem y=2/3x+3, the slope is 2/3, right?" Commas can make all the difference; I just wanted to make sure you did not get misled with your work. Good luck! :)
anonymous
  • anonymous
terry is right. you need just two points to plot a graph of a straight line. but its better to start with a y intercept first cause you don't have a calculate the abscissa (x cordinate) in that case. so your first point be 3 in the y axis. now either you can find one more point using the method told by terry or you can use the slope (may get hard sometimes) to plot the graph. How to use the slope: \[\tan \theta = m\] so \[\theta = \tan^{-1} m\] find the angle from the above method and draw a line making that angle with the horizontal and passing throug the y -intercept

Looking for something else?

Not the answer you are looking for? Search for more explanations.