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anonymous

  • 5 years ago

What is the formula for solving a triangle with the law of cosines if you have all the side lengths but need to find the angles?

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  1. amistre64
    • 5 years ago
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    c^2 - a^2 - b^2 -------------- = cosC 2ab

  2. amistre64
    • 5 years ago
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    its the law of cosines solved for cosC

  3. amistre64
    • 5 years ago
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    to get the angle youll need to take the consine inverse tho... and keep in mind that cos^-1 spits an angle out in the range of 0 to pi...so adjust as needed

  4. amistre64
    • 5 years ago
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    hah... i see a typo

  5. amistre64
    • 5 years ago
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    /-2ab... | c^2 - a^2 - b^2 | cos^-1 |--------------- | = C ; adjusted of course | -2ab |

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