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anonymous
 5 years ago
A fair die is tossed 4 times. Find the probability of a. at least 2 5s b. at most 3 even numbers c. no more than 1 odd number d. at least 1 prime number e. at most 1 number greater than 4
anonymous
 5 years ago
A fair die is tossed 4 times. Find the probability of a. at least 2 5s b. at most 3 even numbers c. no more than 1 odd number d. at least 1 prime number e. at most 1 number greater than 4

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0to find a), you need to know that P(at least 2 5's) = P(exactly 2 5s) + P(exactly 3 5s) +P(exactly 4 5s)+P(all 5s)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so you can find each of those probabilities and add them. that would be the straight forward way.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the easier way is to consider the complement of P(at least 5) which is P(at most 1)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0that way all you have to do is calculate P(at most 1 5s) = P(no 5) + P(exactly 1 5)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Then you can use the fact that P(event A) = 1  P( complement of event A)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0does that help you at all ?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0From the looks of it, all problems I see here becomes much easier if you use P(A) = 1P(notA) let me know if you still need help

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0how about the other parts?
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