anonymous
  • anonymous
A fair die is tossed 4 times. Find the probability of a. at least 2 5s b. at most 3 even numbers c. no more than 1 odd number d. at least 1 prime number e. at most 1 number greater than 4
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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yuki
  • yuki
to find a), you need to know that P(at least 2 5's) = P(exactly 2 5s) + P(exactly 3 5s) +P(exactly 4 5s)+P(all 5s)
yuki
  • yuki
so you can find each of those probabilities and add them. that would be the straight forward way.
yuki
  • yuki
the easier way is to consider the complement of P(at least 5) which is P(at most 1)

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yuki
  • yuki
that way all you have to do is calculate P(at most 1 5s) = P(no 5) + P(exactly 1 5)
yuki
  • yuki
Then you can use the fact that P(event A) = 1 - P( complement of event A)
yuki
  • yuki
does that help you at all ?
yuki
  • yuki
From the looks of it, all problems I see here becomes much easier if you use P(A) = 1-P(notA) let me know if you still need help
anonymous
  • anonymous
how about the other parts?

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