## anonymous 5 years ago Use the quadartic formula to solve the equation below. 2x^2+13x=4

1. anonymous
2. anonymous

Do you mean quadratic? Use the formula and plug in the coeff of the x^2 for a, the coeff of the x term for b and the coeff of the constant term for c. 2x^2+13x=4 ---> 2x^2+13x-4 2x^2--->a=2 13x------>b=13 -4---->c=-4

3. anonymous

-b + or - sqrt(b^2-4ac) all divided by 2a

4. anonymous

Hold on i have chocies

5. anonymous

it would be better to say plus and minus, you get two answers

6. anonymous

they should both work as solutions to the equation

7. anonymous

If you're doing homework they probably want both answers.

8. anonymous

A.) x= 13+√201 -------------- 2 B.)x=-13+√177 ---------------- 4 C.) x= -13+√ 201 ---------------- 2 D.) x= -13 +√ 201 ----------- 4

9. anonymous

AND + HAS a line under it $\pm$

10. anonymous

Close, not quite.

11. anonymous

substitute your values in the quadratic formula and see which is the correct one.

12. anonymous

B?

13. anonymous

what's the difference between C and D

14. anonymous

no.

15. anonymous

c has a 2 and d has a 4

16. anonymous

Well the answer is exactly the same as D, only it's + and - sqrt201

17. anonymous

katie, there is no point guessing the answer. take some time and substitute your vlues into the quadratic equation. that will give you the correct answer.

18. anonymous

so its D?

19. anonymous

If the + is a + - line thing, yes

20. anonymous

±

21. anonymous

yes it has this $\pm$ under it so its D

22. anonymous

Yeah, i mean it's exactly the same as the formula, it just matters that you plug in the right numbers.

23. anonymous

okay thanks

24. anonymous

np

25. anonymous

26. anonymous

I've gotta go, goodluck

27. anonymous

Thanks