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anonymous
 5 years ago
x^2+y=120
find y.
what is the max area?
(the problem is this: a rectangle and a fence to cover 3 sides, find area of the longest side.)
anonymous
 5 years ago
x^2+y=120 find y. what is the max area? (the problem is this: a rectangle and a fence to cover 3 sides, find area of the longest side.)

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Is the Perimeter = 120?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0WELL THE FENCING NEED FOR 3 SIDES IS 120

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0o.k. then 2x + y = 120 because two of the sides are the same, 2x, and the other side doesn't have to be, y. so using this equation you get y = 120  2x Area = Length * Width = y * x = (120  2x)*x That is A = 120x  2x^2 or prettier: \[A = 120x 2x^2\] This is an upside down parabola so the maximum will be at the vertex. When you find the x value of the vertex, plug it into the equation \[A = 120x 2x^2\] to get the maximum area Does that help?
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